= proportion of motorists who check their cell phones while drivingA traffic officer believes that the percentage of motorists who check their cell phones while driving is different from 50%.Identifies:a) The research hypothesis H1b) The null hypothesis HOc) The rejection region of the null hypothesisO a) H;: p = 0.5b) Họ: p + 0.5c) [z, 00)O a) H;: p + 0.5b) Họ: p = 0.5c) (-00, -z]O a) H;: p = 0.5b) Hо: р 2 0.5c) (-00 , -z] U [z, 0)O a) H;: p + 0.5b) Họ: p = 0.5c) (-00, -z] U [z, 0)

Solution: Given that: p= 0.50 Population proportion of motorists who check their cell phones…

Answered: p= proportion of motorists who check…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Every year, high school graduates who want to enroll in the University of the Philippines are required to take the UP College Admission test (UPCAT). Given below are the high school averages and the UPCAT scores of 30 student applications of U.P. Assuming that the assumptions are met, test the hypothesis that p=0 against the alternative that p # 0 at the 0.05 level of significance. High School Average 88.46 81.56 Student UPCAT No. Score 1 57.30 63.80 3 81.00 91.94 4 56.80 87.36 5 62.40 87.00 6. 52.30 81.41 59.70 85.64 8. 71.50 91.83 9. 68.00 82.43 89.39 10 58.40 11 56.90 82.33 12 53.30 86.35 13 62.90 85.68 14 67.40 80.72 15 68.30 85.91 56.80 86.17 86.59 16 17 48.20 65.10 18 85.17 19 66.90 87.36 20 58.10 88.30 21 60.10 88.17 22 57.10 87.18 23 51.90 89.55 24 61.50 88.17 25 54.80 82.73 26 53.30 86.35 27 62.90 85.68 28 58.60 90.91 29 67.40 81.27 30 62.40 88.61
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.01 significance level. The null and alternative hypothesis would be: A.)H0:pM=pF H1:pM>pF B.)H0:pM=pF H1:pM≠pF C.)H0:μM=μF H1:μM≠μF D.)H0:pM=pF H1:pM<pF E.)H0:μM=μF H1:μM>μF F.)H0:μM=μFH0:μM=μF H1:μM<μFH1:μM<μF The test is: A.) left-tailed B.) right-tailed C.) two-tailed Based on a sample of 60 men, 30% owned catsBased on a sample of 60 women, 50% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: A.) Fail to reject the null hypothesis B.) Reject the null hypothesis
A concerned group of citizens wanted to know if the proportion of armed robberies in Texas was different in 2011 than in 2010. Their research showed that of the 113,231 violent crimes in Texas in 2010, 7,622 of them were armed robberies. In 2011, 7,439 of the 104,873 violent crimes were in the armed robbery category. Test at a 5% significance level.a) The null and alternative hypothesis would be: �0:�2010=�2011�1:�2010≠�2011 �0:�2010=�2011�1:�2010<�2011 �0:�2010=�2011�1:�2010≠�2011 �0:�2010=�2011�1:�2010>�2011 �0:�2010=�2011�1:�2010>�2011 �0:�2010=�2011�1:�2010<�2011 b) Determine the test statistic. Round to two decimals.�=c) Find the p-value and round to 4 decimals.p = d) Make a decision. Fail to reject the null hypothesis Reject the null hypothesis e) Write the conclusion. There is not sufficient evidence to support the claim that the proportion of armed robberies is different in 2011 than 2010. There is sufficient evidence to support the claim that the…
20. Which of the following is a null hypothesis? a. Pregnant women who drink cranberry juice will have lower urine bacterial counts than those who do not drink cranberry juice. b. The urine bacterial count of pregnant women who drink cranberry juice will be lower or equal to that of pregnant women who do not drink the juice. c. There will be a difference between ingestion of cranberry juice and among pregnant women who do and do not have high urine bacterial counts.
In a study of high school students at least 16 years of age, researches obtained data summarized in the table below. Test the claim that texting while driving is independent of drinking alchohol and driving. Assume a significance level of 0.05. Drove when Drinking Did not drive when Drinking Totals Texting while Driving 731 3054 3785 No Texting and Driving 156 4564 4720 Totals 887 7618 8505 c) What is the Alternative Hypothesis? d) Which type of test will be used? e) What critical values are there?
Q2)A two sided hypothesis test is performed about a population proportion p.The valid alternative hypothesis is :- (choose the correct option) • p=0.4 ⚫ p0.9 • p0.6
A survey and research company claims that TV network A garnered 31% audience satisfaction. To test the claim, TV network A conducted a survey from 2000 randomly selected viewers all over the country with a 0.05 significance level. Which of the following is the correct null and alternative hypothesis? O a. H.: p > 0.69 Ha:p = 0.69 %3D O b. H.:p 0.31
7)
Machines at a factory are supposed to dispense 250 grams of sugar per pack. A random sample of sugar packs is taken from the factory, and their contents (in grams) are measured. Following are the sample data: 247 247 247 248 249 250 250 250 251 251 Is there sufficient evidence to conclude that the machines do not conform to the indicated sugar amount? Use 0.10 level of significance. Which case for hypothesis testing must be used? ( Select ] What is the alternative hypothesis? ( Select ] What is the value of the test statistic? [ Select ] What is/are the critical value/s? Select ] What is the appropriate conclusion? [Select
What do you conclude? a.) No, it is not longer. b.) Yes, it is longer. c.) Results are invalid due to the t-stat. d.) Results are invalid due to the small sample size.
10) In a survey of 500 cigarette smokers, 39 of them reported that they have tried hypnosis therapy to try to quit smoking.. Can you conclude that less than one-tenth of smokers have tried hypnosis therapy? Use the a = 0.05 level of significance. %3D A) No B) Yes C) No conclusion is possible.
Suppose we run a two-tail hypothesis test that uses the Student's t-distribution with 16 degrees of freedom and a level of significance of 0.05. What would be the appropriate critical values for this test? a) ww b) Both a and b are correct. Neither a nor b are correct. t = 1.746 b= -1.746

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