P Let Q represent a mass (in grams) of carbon (14C), whose half-life is 5,715 years. The quantity of carbon-14 present after t years is given by the following =6(1) 1/5,715 (a) Determine the initial quantity (when t = 0). Q = (b) Determine the quantity present after 3000 years. (Round your answer to two decimal places.) (c) Sketch the graph of the function over the interval t = 0 to t = 10,000.
P Let Q represent a mass (in grams) of carbon (14C), whose half-life is 5,715 years. The quantity of carbon-14 present after t years is given by the following =6(1) 1/5,715 (a) Determine the initial quantity (when t = 0). Q = (b) Determine the quantity present after 3000 years. (Round your answer to two decimal places.) (c) Sketch the graph of the function over the interval t = 0 to t = 10,000.
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter10: Exponential And Logarithmic Functions
Section10.CT: Test
Problem 21CT
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Let Q represent a mass (in grams) of carbon (14C), whose half-life is 5,715 years. The quantity of carbon-14 present after t years is given by the following.
= 6(-1) 1/5,715
Q =
(a) Determine the initial quantity (when t = 0).
9
(b) Determine the quantity present after 3000 years. (Round your answer to two decimal places.)
(c) Sketch the graph of the function over the interval t = 0 to t = 10,000.
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85°F Partly sunny](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2fc418c4-8f1a-4611-b0fb-a49c5f70461b%2Feebc9584-08d1-4a15-bbd3-9f7efa4b6fcd%2F4fqb549_processed.jpeg&w=3840&q=75)
Transcribed Image Text:+
Let Q represent a mass (in grams) of carbon (14C), whose half-life is 5,715 years. The quantity of carbon-14 present after t years is given by the following.
= 6(-1) 1/5,715
Q =
(a) Determine the initial quantity (when t = 0).
9
(b) Determine the quantity present after 3000 years. (Round your answer to two decimal places.)
(c) Sketch the graph of the function over the interval t = 0 to t = 10,000.
80
70-
60-
50-
40
30-
25
20
0
2000 4000 6000
Type here to search
1
8000 10000
O
O
Q
20
18-
16
14
12-
10
8-
6
0
Et
2000 4000 6000 8000
1
10000
81
7
6-
5-
Q4
3
2
0
14
2000
4000
1
6000 8000 10000
85°F Partly sunny
![Q
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Transcribed Image Text:Q
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