p) After 6 months, what is the p stribution as based on part (a). =) After 2 years, what is the pro d) Compare your answers to pa O Yes O No Why would this happen? The standard deviation (e) If after 2 years the average has slipped below 1.9%? Explair O This is very likely if u = if Lu

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A certain mutual fund invests in both U.S. and foreign markets. Let x
a random variable that represents the monthly percentage return for the fund. Assume x has mean u = 1.9% and
standard deviation o = 0.3%.
(a) The fund has over 175 stocks that combine together to give the overall monthly percentage return x. We can consider the monthly return of the stocks in the fund to be a
sample from the population of monthly returns of all world stocks. Then we see that the overall monthly return x for the fund is itself an average return computed using all 175
stocks in the fund. Why would this indicate that x has an approximately normal distribution? Explain. Hint: See the discussion after Theorem 6.2.
The random variable
-Select-v is a mean of a sample size n = 175. By the -Select-
v, the -Select- distribution is approximately normal.
(b) After 6 months, what is the probability that thẹ average monthly percentage return x will be between 1% and 2%? Hint: See Theorem 6.1, and assume that x has a normal
distribution as based on part (a). (Round your answer to four decimal places.)
(c) After 2 years, what is the probability that x will be between 1% and 2%? (Round your answer to four decimal places.)
(d) Compare your answers to parts (b) and (c). Did the probability increase as n (number of months) increased?
O Yes
O No
Why would this happen?
as the
-Select-- v increases.
The standard deviation -Select--
(e) If after 2 years the average monthly percentage return was less than 1%, would that tend to shake your confidence in the statement that u = 1.9%? Might you suspect that u
has slipped below 1.9%? Explain.
O This is very likely if u = 1.9%. One would suspect that u has slipped below 1.9%.
O This is very unlikely if u = 1.9%. One would suspect that Lu has slipped below 1.9%.
O This is very unlikely if u = 1.9%. One would not suspect that u has slipped below 1.9%.
19% One would not suspect that u has slinned below 1.9%
US 2 • A 2:52
O This is very likely if u
hp
Transcribed Image Text:A certain mutual fund invests in both U.S. and foreign markets. Let x a random variable that represents the monthly percentage return for the fund. Assume x has mean u = 1.9% and standard deviation o = 0.3%. (a) The fund has over 175 stocks that combine together to give the overall monthly percentage return x. We can consider the monthly return of the stocks in the fund to be a sample from the population of monthly returns of all world stocks. Then we see that the overall monthly return x for the fund is itself an average return computed using all 175 stocks in the fund. Why would this indicate that x has an approximately normal distribution? Explain. Hint: See the discussion after Theorem 6.2. The random variable -Select-v is a mean of a sample size n = 175. By the -Select- v, the -Select- distribution is approximately normal. (b) After 6 months, what is the probability that thẹ average monthly percentage return x will be between 1% and 2%? Hint: See Theorem 6.1, and assume that x has a normal distribution as based on part (a). (Round your answer to four decimal places.) (c) After 2 years, what is the probability that x will be between 1% and 2%? (Round your answer to four decimal places.) (d) Compare your answers to parts (b) and (c). Did the probability increase as n (number of months) increased? O Yes O No Why would this happen? as the -Select-- v increases. The standard deviation -Select-- (e) If after 2 years the average monthly percentage return was less than 1%, would that tend to shake your confidence in the statement that u = 1.9%? Might you suspect that u has slipped below 1.9%? Explain. O This is very likely if u = 1.9%. One would suspect that u has slipped below 1.9%. O This is very unlikely if u = 1.9%. One would suspect that Lu has slipped below 1.9%. O This is very unlikely if u = 1.9%. One would not suspect that u has slipped below 1.9%. 19% One would not suspect that u has slinned below 1.9% US 2 • A 2:52 O This is very likely if u hp
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