P, = 4.5kN W, = 2.4kN/m W2 = 1.6kN/m P2 = 3.6kN 2.1m 0.9m 1m 1.5m 1.5m 7m

Q: 12 m 25 kN/m

A:

Q: 3.19 Calculate the reactions at the built-in support at C, neglecting the weights of the members.…

A:

Q: The Frame is hinged at rigid supports in A & E. Find the components of the reaction at A and E and…

A: To find support reaction and force in member BC,BD

Q: 8k/ft 4 k/ft 30 ft

A:

Q: The reaction at support A RAy and reaction at support C RCy b- The bending moment at B…

A:

Q: 10 kN/m 10 kN/m C 5 m D 4 m 6 m

A:

Q: Determine the reactions at the supports. 350 N/m 150 N/m 80 N/m 3.5 m 4.5 m

A:

Q: Given the beam loaded as shown. 60 KN 3 m 50 kN/m 10 kN-m A 1m 5 m

A:

Q: 60 kNim 120 N 30 kN 10 kN/m 2m 2m 2 m 6 m

A: Support A is roller support so there will be only one reaction - vertical reaction VA. Support B  is…

Q: determine the reactions and draw the shear bending moment diagrams for the beams using method of…

A: Given: Required: Reaction and shear force and bending moment diagram

Q: supports for the beam shown. 25 kN/m В 12 m A

A:

Q: d. Find the reactions at the supports. Major topic - Stiffness Method of AN Analysing Structures 400…

A: solution: Analyse the pin joint truss by stiffness matrix method ∆=K-1×P Element Coordinate forces…

Q: Calculate the reactions at supports. 400 N/m 400 N/m 3 m

A: The given beam is analyzed by using the equations of equilibrium forces.  The algebraic sum of…

Q: and frames shown.Draw the FD

A:

Q: PROBLEM 2 Determine the reactions at the supports at A, B and D. Assume that A is roller and B is a…

A: A frame is hinged at B and the roller is supported at A, with loading as shown. To determine the…

Q: Determine the reactions at the supports A and B and Draw a free body diagram

A: We have to determine the reactions at supports A and B

Q: Practice Problem #5) Determine the reactions at the supports for the beam

A: Step 1: Given Data:A 50 kN point load at A, inclined at 30° to the horizontal.A distributed load of…

Q: What is the maximum positive moment for the beam shown? Use the method of consistent deformations.…

A:

Q: Determine the reaction (kN) at support A from the given structure. 600 lb/ft 400 lb/ft 20 ft A B 48…

A: To find reaction at support A

Q: 600 N _0.75 m 0.5 m 0.75 m 500 N

A: According to given data  Determine the components of reaction at the fixed support A. The 400 N, 500…

Q: 6 kN/m 6 kN/m 3 kN/m B A - 3 m 3 m

A:

Q: The ramp of a ship has a weight of 200 lb and a center of mass at G. The ramp is attached to the…

A: The given figure is shown below:

Q: SHOW THE FBD. SOLVE THE SUPPORT REACTIONS OF THE FOLLOWING STRUCTURE: BEAMS 4 kN/m 2 kN/m A В 3 m 3…

A:

Q: Determine the reactions at supports A and B, and the bar force in bar AC of the truss shown in the…

A: ∑Fy=0VA+VB=24+16=40FX=0HA=HB=0∑MB=0VA×3×a-16×2×a+24×a=0VA=2.67 KNAnd   VB=37.33 KN

Q: Determine the reactions at the support if F1 = 8kN, F2 = 4kN, F3 = 3kN. %3D %3D %3D F,

A: Reactions actingAx, Ay and MA

Q: Solve for the support reactions at A and B

A:

Q: he horizontal and vertical components of

A:

Q: STATICS AND EQUILIBRIUM- REACTIONS/SUPPORT The truss is supported by a pin at point A and a roller…

A:

Q: Q. Determine the support reactions of the shown beam Fixed 2 kN 3 kN. m A 2 m 1 m 1.5 m 1.5 m

A:

Q: 0.8 m 0.7 m Ax C B 25 degree Ay 200 kg Dx D Dy Q) Find the reactions at A and D which are pinned…

A:

Q: Determine the reactions on the beam. 5 k/ft -24 ft 2 k/ft B 10 ft Ray = Rax = Rby = Rbx = RB ||

A: Determine the reactions on the beam.

Q: determine the reactions at the supports of the beam.

A:

Q: Name (Chinese), Q1 a) Calculate the reactions at the supports A and E. b) Draw the shear force…

A: Note:- As the question is with sub parts, so as per policy of Bartlby we will provide answer to…

Equilibrium and Support Reactions

Civil engineers deal with structures that are composed of several members connected or with individual members such as beams and columns. To analyze such structures, the condition of statics must be applied. Under the static condition, the members are considered to be in equilibrium under the action of forces, that is, the members are assumed to be having negligible velocity.