P(-2

Q: How would you interpret F (2, 30) = 32.60, p < .05?

A:

Q: The values for P(A₁ B) and P(A₂B) were found to be 0.20 and 0.02, respectively. Use these values to…

A: P(A1⋂B)=0.20, P(A2⋂B)=0.02

Q: Calculate P (-0.1 < Z < 0.1). (Round to the hundredths).

A:

Q: P(z<2.25)=

A: Given Information: To find out Pz&lt;2.25

Q: P(Z > 0.98)=

A:

Q: X~N(1.8, 0.4).  Find P(0.9 < X < 2.3).  (Round to 3 decimal places.)

A:

Q: P(z< ( Or equal to ) z0) = 0.7054

A:

Q: P(1.10 s z) P(IZ| s 2.50)

A: Here use normal distribution table for probability from z score

Q: P(z>1.2)

A: Given problem Given that   P(z&gt;1.2)   Ans) P( z&gt;1.2 ) is, = 1 - P( z ≤ 1.2 )

Q: Find P(F<2.95) nu1=12 nu2=12 Make sure to show your work.

A: nu1=12nu2=12

Q: Answers are wrong z=2.712 not 2.714 Where are the rest of the answers.. this is incomplete and…

A: a) The hypotheses for the test are given below: Null hypothesis: H0: p = 0.35 Alternative…

Q: X 0 1 2 3 P(X = x) |0.512 0.384 0.096 0.008 Find P(more than 2 identifications are incorrect).

A: From the provided information, x 0 1 2 3 P (X = x) 0.512 0.384 0.096 0.008…

Q: P(Z<1.89) (less than or equal to)

A: Given that.   X~N( 0 , 1 )   μ=0  , ?=1 (for standard normal distribution)    Z-score =( x - μ )/?

Q: find P (Z > 1.21) = find P (Z < 1.60) = find P (0.59 < Z < 1.78) =

A: 1) P (Z &gt; 1.21) =?

Q: X~N(43.8, 3.5).  Find P(X < 37.0).  (Round to 3 decimal places.)

A: The following is the formulae for z-score                                    z = X-μσ where μ is the…

Q: Assume P(Z> b) = 0.35 for some number b. Without finding the value of b, what P(Z < – b)?

A:

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: P(-1.33<z<0)= round answer to four decimal places as needed

A: The z-scores are -1.33 and 0.

Q: P(z < -2.61)

A: Z score = -2.61 Left tailed test

Q: p(-c<z<c)=0.9464

A: P(-c&lt;z&lt;c)=0.9464

Q: Calculate P(z<-1.2)

A: The z-score is standard normal variable with mean 0 and standard deviation 1.

Q: can you explain how you found the values for H(t-3)

A: We have to explain how we got the value of H(t-3) and H(t-1) and H(t)-H(t-3)

Q: P(X ≤ 1). n = 5, p = 0.6

A:

Q: P ( -2.53 &lt; z &lt; 0.65)

A: The probability is,

Q: P(- c ≤ Z ≤ c)=0.9399

A: We have given that  P(- c ≤ Z ≤ c)=0.9399 From the given information we have to find the value of c

Q: ind P(|Z| ≤ 2.5). (round to three decimal places.

A: given data  standard normal curve Z~N(0,1) P(|Z|≤2.5) = ?

Q: p(0.7 <z < 1.31) =

A: Answer - Find P( 0.7 &lt; Z &lt; 1.31)  = ?

Q: what is p(z<?)=0.88

A:

Q: P(z2.57)

A: Let Z be the random variable from normal distribution then we will find the Probability P(z&lt;1.53…

Q: Suppose X - x²(13). Find P(8.093 < X < 21.637). Round your answer to 2 decimals. P(8.093 < X <…

A:

Q: Find: x=  m<P= m<Q=

A: We have to solve