oY sistarm 6 o х Se uivioz 1 24 еa 9x = 6.24 Sc avo uoy co oio 9x = 144 М X 16 Find the length of the indicated side, x, by setting up a proportion. 45) 28 7 enx 90 14 eenbjc 20 ameldo nots 5 wa 46) staib or 12 18 32 9 adt 16dh 10 24

Q: Solve. 31 +35(2¹) = 74 X - Round to 4 decimal places.

A:

Q: Solve for y. x + 2 x + 4 X y+ 6 14

A: Given ,  We have to solve for y

Q: solve formula За(1-5b)=2b-4а

A:

Q: Solve. 3 -3 = √4x - 3

A: -3=4x-33

Q: Solve for X

A: Given, 32-x= 52x+1

Q: . Solve: 2x + 3 = 9

A: To solve the equation: 2x+3=9 Solution:' Given equation is 2x+3=9. Solving the given equation.…

Q: Solve for m. -3+m = 10          /9

A: To solve for m

Q: 3. 3 2 P + 40 -7P+2 }}

A: Given differential equation  D3+4D2-7D+2=0

Q: B

A: Given,  A circle with tangent BD and secant BC  We have to find the value of x.

Q: Solve 2 +125=0

A:

Q: . Solve exactly: ex-4 = 6

A: Solve exactly: ex-4 = 6

Q: Solve for xx: 4x=23

A: use the basic operation of multiplication.

Q: Solve. 9y-6(2y-14)=75

A:

Q: Solve 3/I + 10 – 5 = 4 for z न ]

A:

Q: 7. solve the following x+2 X-2

A:

Q: solve for x, x+96=90

A: In the given diagram, we see that the measure of the indicated angle ( ) is .

Q: Q Solve for X In4x-3lnx

A: Given: ln4x-3lnx2=ln2

Q: SOLVE FOR x & y M 40 K Y.

A: The value of the x and y needs to be evaluated

Q: Solve for x+69=89

A: Here we want to solve  x + 69 = 89

Q: solve the equtions 31

A: Givent3y'=2ywhere y(1)=1and t>0

Q: 14 28

A: Follow next step

Q: Solve for x: A 2B x+3

A:

Q: Solve for r. 6. 54

A:

Q: and

A: We have to find the value of x and y according to the given information

Q: Solve for “B” 5:a:13 = b:7:3

A: The detailed solution is as follows below:

Q: EK+L=D-UK Solve for K

A: The given equation is EK+L=D-UK.

Q: 18

A:

Q: Use the annihilator method to sodve y"+y'-by=2x+1 - 3e* ; yo) =O yce) = 3 %3D

A: Annihilators: Let f is a function, then annihilator of f is a "differential operator"…

Q: Solve. (a-4)(a+7)=0

A: We need to solve the equation (a−4)(a+7)=0

Q: 2x x + 2 12 8

A:

Q: Solve /-2 +15 2

A:

Q: Solve for h. 2(h + 5) - h = h + 10

A:

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.