oxygen, O2, via the following process:   2O3(g) → 3O2(g)   The rate law for the decomposition of ozone to molecular oxygen is   rate = k[O3]2/ [O2]  The mechanism proposed for this process is   O3 = O + O2 (equilibrium k1 is forward and K-1 is reverse)   O + O3 = 2O2 (k2)   What is the rate law in terms of k1, k2, and k−1?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Derive the rate law for the decomposition of ozone (in terms of k1k2, and k−1) from the following steps.
 
Ozone, O3, decomposes to molecular oxygen, O2, via the following process:
 
2O3(g) → 3O2(g)
 
The rate law for the decomposition of ozone to molecular oxygen is
 
rate = k[O3]2/ [O2
The mechanism proposed for this process is
 
O3 = O + O2 (equilibrium k1 is forward and K-1 is reverse)
 
O + O3 = 2O2 (k2)
 
What is the rate law in terms of k1k2, and k−1?

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