Oxygen gas can be prepared by heating potassium chlorate according to the following equation:2KClO3(s)2KCl(s) + 3O2(g)The product gas, O2, is collected over water at a temperature of 20 °C and a pressure of 741 mm Hg. If the wet O2 gas formed occupies a volume of 8.97 L, the number of moles of KClO3 reacted was _____ mol. The vapor pressure of water is 17.5 mm Hg at 20 °C. Find the number of moles of KClO3 reacted.
Oxygen gas can be prepared by heating potassium chlorate according to the following equation:2KClO3(s)2KCl(s) + 3O2(g)The product gas, O2, is collected over water at a temperature of 20 °C and a pressure of 741 mm Hg. If the wet O2 gas formed occupies a volume of 8.97 L, the number of moles of KClO3 reacted was _____ mol. The vapor pressure of water is 17.5 mm Hg at 20 °C. Find the number of moles of KClO3 reacted.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Oxygen gas can be prepared by heating potassium chlorate according to the following equation:
2KClO3(s)2KCl(s) + 3O2(g)
The product gas, O2, is collected over water at a temperature of 20 °C and a pressure of 741 mm Hg. If the wet O2 gas formed occupies a volume of 8.97 L, the number of moles of KClO3 reacted was _____ mol. The vapor pressure of water is 17.5 mm Hg at 20 °C. Find the number of moles of KClO3 reacted.
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