Ox 0₂ V = Ox x Find the bulk modulus K (in psi) for the aluminum if the following stress and strain data are known: normal stresses are dx = 5,000 psi (tension), y = -4,300 psi (compression); and ₂ = -4,400 psi (compression) and normal strains in the x and y directions are & = 787.1 x 10-6 (elongation) and &y=-449.8 x 10-6 (shortening). psi If the element is replaced by one of steel, find the modulus of elasticity E (in ksi) and Poisson's ratio v if the following data is given: bulk modulus K = 2.3 × 107 psi; normal stresses are x = 4,350 psi (tension), y = -1,250 psi (compression), and ₂ = -2,400 psi (compression); and normal strain in the x direction is = 182 x 10-6 (elongation). (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including in WebAssign.) answers submitted E = ksi

Ox 0₂ V = Ox x Find the bulk modulus K (in psi) for the aluminum if the following stress and strain data are known: normal stresses are dx = 5,000 psi (tension), y = -4,300 psi (compression); and ₂ = -4,400 psi (compression) and normal strains in the x and y directions are & = 787.1 x 10-6 (elongation) and &y=-449.8 x 10-6 (shortening). psi If the element is replaced by one of steel, find the modulus of elasticity E (in ksi) and Poisson's ratio v if the following data is given: bulk modulus K = 2.3 × 107 psi; normal stresses are x = 4,350 psi (tension), y = -1,250 psi (compression), and ₂ = -2,400 psi (compression); and normal strain in the x direction is = 182 x 10-6 (elongation). (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including in WebAssign.) answers submitted E = ksi

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Strain energy

The term strain indicates the variation in an object's length, area, and volume when the object is subjected to an external force. The external force may be of normal, shear, moment, torque, etc. The strain in an object depends on the types of external force and cross-section of the object. Mathematically, the evaluation of strain can be obtained with the help of elastic constants.

Question

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An element of aluminum is subjected to triaxial stress (see figure).
=
6
Ox
V =
or
lo
O₂
Ox
Oy
i
=
(a) Find the bulk modulus K (in psi) for the aluminum if the following stress and strain data are known: normal stresses are ox
oy -4,300 psi (compression); and σ₂ = −4,400 psi (compression) and normal strains in the x and y directions are &
Z
X
Ey
= -449.8 x 10-6 (shortening).
psi
X
5,000 psi (tension),
787.1 x 10-6 (elongation) and
(b) If the element is replaced by one of steel, find the modulus of elasticity E (in ksi) and Poisson's ratio v if the following data is given: bulk modulus
K = 2.3 × 107 psi; normal stresses are ox 4,350 psi (tension), Gy -1,250 psi (compression), and σ₂ = −2,400 psi (compression); and normal strain in
=
=
Z
=
the x direction is ex 182 x 10-6 (elongation). (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including
answers submitted in WebAssign.)
E =
ksi

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