Over alphabet (a, b). Hint: Symbol A is another notation for empty string (2) Start Λ Λ b 1 2
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This is automata theory. Convert the following NFA to equivalent DFA. (B) Show the steps for the conversion.
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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringDon't copy ASAPQ: Write regular expression for the following languages. All strings in which b is never tripled. It means that no words contain the substring bb. All the strings accepting b as second letter. Regular expression that accept only prime numbers. All the strings that start with aa, end with bb, and have alternating substrings ba in between. Language of all those strings with length greater than 3
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…Correct answer will be upvoted else Multiple Downvoted. Computer science. You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'. A string is called a regular bracket sequence (RBS) if it's of one of the following type empty strin '(' + RBS + ')' '[' + RBS + ']' RBS + RBS where plus is a concatenation of two strings In one move you can choose a non-empty subsequence of the string s (not necessarily consecutive) that is an RBS, remove it from the string and concatenate the remaining parts without changing the order What is the maximum number of moves you can perfor Input The first line contains a single integer t (1≤t≤1000) — the number of testcases Each of the next t lines contains a non-empty string, consisting only of characters '(', ')', '[' and ']'. The total length of the strings over all testcases doesn't exceed 2⋅10 Output For each testcase print a single integer — the maximum number of moves you can perform on a given string…Write a regular expression that defines strings that have an even (but nonzero) number of "a" characters followed by an odd number of "b" characters. For example, aab, aabbb, aaaab, and aaaabbb should all match the regular expression.