OVE a) Same aromatic product from left and right. Hint: Look carefully at both starting materials for helpful clues! habla H “CH,CH,ONa H CH3 b) Do EITHER LEFT OR RIGHT. If you have time at the end to do both, I will take your best one. (H₂SO4) CH₂OH -H₂O blo O CH₂ AICI 3 OH NaOCH 3 Ha
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![**Exercise Description:**
**a) Reaction Pathways:**
- The diagram shows two reactions leading to the same aromatic product. Carefully examine both starting materials to identify helpful clues for the transformation.
**b) Optional Reaction Path:**
- This section gives a choice between two synthesis routes. Do either left or right. If time allows, performing both could be beneficial.
**Pathway on the Left:**
1. Starting Material: Benzene with an amine group (NH₂).
2. Reagents and Conditions:
- First step: Use HONO/H₂SO₄
- Second step: Use CuCN
3. Product A: __[Product A structure not described]__
**Pathway on the Right:**
1. Starting Material: Aromatic compound with an aldehyde group.
2. Reagents and Conditions:
- H₂SO₄, CH₃OH (Sulfuric acid and methanol)
- NaOCH₃ (Sodium methoxide)
3. Product B: __[Product B structure not described]__
**Final Reaction:**
- Starting material from any path is reacted with AlCl₃
- Resultant compound is an aromatic product with a carbonyl group.
**Instructions:**
- Select any two products (A, B, or C) from the sequences provided. If you complete all three, choose the best examples. Note: substituting DCC with Iso-butyl chloroformate in the final step achieves the same result.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96c43769-2331-4d91-b7f9-4a256a33e785%2F9f88d1ee-6115-4804-99ec-7ee3b49d21b3%2Fg1apbl_processed.jpeg&w=3840&q=75)
Step by step
Solved in 4 steps with 3 images
