Output Table: ID: 123 ; Name: Enan ; CGPA: 2.75 ; Exams: 80, 70, 85, 75 ; Average Mark: 80 ID: 131 ; Name: Akash ; CGPA: 2.72 ; Exams: 80, 70, 65, 75; Average Mark: 75 ID: 132 ; Name: Shovon ; CGPA: 2.7; Exams: 75, 75, 75; Average Mark: 75 ID: 141 ; Name: Tanvir ; CGPA: 3.3 ; Exams: 80, 90, 85, 80, 90; Average Mark: 88.33 ID: 142 ; Name: Junayet ; CGPA: 2.5 ; Exams: 75, 80, 70 ; Average Mark: 75 Note: The Student list will be printed in ascending order based on student ID. Average Mark: You have to take best 3 exam marks. (From the number of exams were taken) For example, you have to take 5 best exam marks if the number of exams is 7. And then you have to take the average. In our example, the number of exams was 5. That's why the average number was based on 3 best exam marks.
Output Table: ID: 123 ; Name: Enan ; CGPA: 2.75 ; Exams: 80, 70, 85, 75 ; Average Mark: 80 ID: 131 ; Name: Akash ; CGPA: 2.72 ; Exams: 80, 70, 65, 75; Average Mark: 75 ID: 132 ; Name: Shovon ; CGPA: 2.7; Exams: 75, 75, 75; Average Mark: 75 ID: 141 ; Name: Tanvir ; CGPA: 3.3 ; Exams: 80, 90, 85, 80, 90; Average Mark: 88.33 ID: 142 ; Name: Junayet ; CGPA: 2.5 ; Exams: 75, 80, 70 ; Average Mark: 75 Note: The Student list will be printed in ascending order based on student ID. Average Mark: You have to take best 3 exam marks. (From the number of exams were taken) For example, you have to take 5 best exam marks if the number of exams is 7. And then you have to take the average. In our example, the number of exams was 5. That's why the average number was based on 3 best exam marks.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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