Please help me find the C language code of this. Thank You! Outputmain.c>+1#include1. Respond baaaack22. Respond - baaaack3. Respond - baaaack4. Respond - baaaackvoid spam1();4 void spam2();36- int main(void) {5. Respond baaaack71. Lionel Richieee8// TODO: Call spam1() and spam2() here 3 times2. Lionel Richieee9.3. Lionel Richieee104. Lionel Richieee11return 0;12 };5. Lionel Richieee131. Respond baaaack2. Respond - baaaack14 - void spam1() {for(int i = 1; i <= 5; i++) {printf("%d. Respond baaaack\n", i);}}15 -3. Respond baaaack164. Respond baaaack17185. Respond baaaack1. Lionel Richieee1920 - void spam2() {2. Lionel Richieeefor(int i = 1; i <= 5; i++) {printf("%d. Lionel Richieee\n", i);}21-3. Lionel· Richieee224. Lionel Richieee235. Lionel Richieee24 }1. Respond baaaack2. Respond - baaaack > + c4. Multiple Callsmain.cby CodeChum Admin1#includeAfter not being so clear with what I wantedto ask, Lionel Richie's starting to ignore me.3 void spam1();4 void spam2();I'm usually patient but sometimes, getting6- int main(void) {ignored is something I really don't like e78// TODO: Call spam1() and spam2() here 3 timesOh, I know! I'll bombard him with a lot of9.calls!1011return 0;12 };13Instructions:14 - void spam1() {for(int i = 1; i <= 5; i++) {printf("%d. Respond baaaack\n", i);}15 -1. In the code editor, you are providedwith an empty main() code as well astwo completely defined functions,spam1() and spam2()2. In the main(), call these two functionsinterchangeably starting with spam1()and then spam2().161718 }1920 - void spam2() {for(int i = 1; i <= 5; i++) {printf("%d. Lionel Richieee\n", i);}21-22233. Do this 3 times.24 3Output

1. #include<stdio.h> is a header file 2. There are two defined functions void spam1() and void…

Output main.c 1 #include 1. Respond baaaack 3 void spam1(); 4 void spam2(); 2. Respond baaaack 3. Respond baaaack 4. Respond - baaaack 5. Respond - baaaack 6- int main(void) { 1. Lionel Richieee // TODO: Call spam1() and spam2() here 3 times 2. Lionel Richieee 3. Lionel Richieee 10 4. Lionel Richieee 11 return 0; 12 }; 13 5. Lionel Richieee 1. Respond - baaaack 2. Respond - baaaack 14 - void spam1() { 15- for(int i = 1; i <= 5; i++) { printf("%d. Respond baaaack\n", i); } 3. Respond baaaack 16 17 4. Respond baaaack 5. Respond baaaack 1. Lionel· Richieee 18 } 19 20 - void spam2() { 2. Lionel Richieee for(int i = 1; i <= 5; i++) { printf("%d. Llionel Richieee\n", i); } 21- 3. Lionel Richieee 22 4. Lionel Richieee 23 5. Lionel Richieee 1. Respond baaaack 24 } 2. Respond baaaack