Output main.c 1 #include 1. Respond baaaack 3 void spam1(); 4 void spam2(); 2. Respond baaaack 3. Respond baaaack 4. Respond - baaaack 5. Respond - baaaack 6- int main(void) { 1. Lionel Richieee // TODO: Call spam1() and spam2() here 3 times 2. Lionel Richieee 3. Lionel Richieee 10 4. Lionel Richieee 11 return 0; 12 }; 13 5. Lionel Richieee 1. Respond - baaaack 2. Respond - baaaack 14 - void spam1() { 15- for(int i = 1; i <= 5; i++) { printf("%d. Respond baaaack\n", i); } 3. Respond baaaack 16 17 4. Respond baaaack 5. Respond baaaack 1. Lionel· Richieee 18 } 19 20 - void spam2() { 2. Lionel Richieee for(int i = 1; i <= 5; i++) { printf("%d. Llionel Richieee\n", i); } 21- 3. Lionel Richieee 22 4. Lionel Richieee 23 5. Lionel Richieee 1. Respond baaaack 24 } 2. Respond baaaack
Output main.c 1 #include 1. Respond baaaack 3 void spam1(); 4 void spam2(); 2. Respond baaaack 3. Respond baaaack 4. Respond - baaaack 5. Respond - baaaack 6- int main(void) { 1. Lionel Richieee // TODO: Call spam1() and spam2() here 3 times 2. Lionel Richieee 3. Lionel Richieee 10 4. Lionel Richieee 11 return 0; 12 }; 13 5. Lionel Richieee 1. Respond - baaaack 2. Respond - baaaack 14 - void spam1() { 15- for(int i = 1; i <= 5; i++) { printf("%d. Respond baaaack\n", i); } 3. Respond baaaack 16 17 4. Respond baaaack 5. Respond baaaack 1. Lionel· Richieee 18 } 19 20 - void spam2() { 2. Lionel Richieee for(int i = 1; i <= 5; i++) { printf("%d. Llionel Richieee\n", i); } 21- 3. Lionel Richieee 22 4. Lionel Richieee 23 5. Lionel Richieee 1. Respond baaaack 24 } 2. Respond baaaack
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
100%
Please help me find the C language code of this. Thank You!
![Output
main.c
>
+
1
#include<stdio.h>
1. Respond baaaack
2
2. Respond - baaaack
3. Respond - baaaack
4. Respond - baaaack
void spam1();
4 void spam2();
3
6- int main(void) {
5. Respond baaaack
7
1. Lionel Richieee
8
// TODO: Call spam1() and spam2() here 3 times
2. Lionel Richieee
9.
3. Lionel Richieee
10
4. Lionel Richieee
11
return 0;
12 };
5. Lionel Richieee
13
1. Respond baaaack
2. Respond - baaaack
14 - void spam1() {
for(int i = 1; i <= 5; i++) {
printf("%d. Respond baaaack\n", i);
}
}
15 -
3. Respond baaaack
16
4. Respond baaaack
17
18
5. Respond baaaack
1. Lionel Richieee
19
20 - void spam2() {
2. Lionel Richieee
for(int i = 1; i <= 5; i++) {
printf("%d. Lionel Richieee\n", i);
}
21-
3. Lionel· Richieee
22
4. Lionel Richieee
23
5. Lionel Richieee
24 }
1. Respond baaaack
2. Respond - baaaack](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffabcd8de-5995-4996-ab40-ec1c9623d1e0%2Fc1b57066-dae4-443f-8d59-4281f4a17188%2F666os9_processed.png&w=3840&q=75)
Transcribed Image Text:Output
main.c
>
+
1
#include<stdio.h>
1. Respond baaaack
2
2. Respond - baaaack
3. Respond - baaaack
4. Respond - baaaack
void spam1();
4 void spam2();
3
6- int main(void) {
5. Respond baaaack
7
1. Lionel Richieee
8
// TODO: Call spam1() and spam2() here 3 times
2. Lionel Richieee
9.
3. Lionel Richieee
10
4. Lionel Richieee
11
return 0;
12 };
5. Lionel Richieee
13
1. Respond baaaack
2. Respond - baaaack
14 - void spam1() {
for(int i = 1; i <= 5; i++) {
printf("%d. Respond baaaack\n", i);
}
}
15 -
3. Respond baaaack
16
4. Respond baaaack
17
18
5. Respond baaaack
1. Lionel Richieee
19
20 - void spam2() {
2. Lionel Richieee
for(int i = 1; i <= 5; i++) {
printf("%d. Lionel Richieee\n", i);
}
21-
3. Lionel· Richieee
22
4. Lionel Richieee
23
5. Lionel Richieee
24 }
1. Respond baaaack
2. Respond - baaaack
![> + c
4. Multiple Calls
main.c
by CodeChum Admin
1
#include<stdio.h>
After not being so clear with what I wanted
to ask, Lionel Richie's starting to ignore me.
3 void spam1();
4 void spam2();
I'm usually patient but sometimes, getting
6- int main(void) {
ignored is something I really don't like e
7
8
// TODO: Call spam1() and spam2() here 3 times
Oh, I know! I'll bombard him with a lot of
9.
calls!
10
11
return 0;
12 };
13
Instructions:
14 - void spam1() {
for(int i = 1; i <= 5; i++) {
printf("%d. Respond baaaack\n", i);
}
15 -
1. In the code editor, you are provided
with an empty main() code as well as
two completely defined functions,
spam1() and spam2()
2. In the main(), call these two functions
interchangeably starting with spam1()
and then spam2().
16
17
18 }
19
20 - void spam2() {
for(int i = 1; i <= 5; i++) {
printf("%d. Lionel Richieee\n", i);
}
21-
22
23
3. Do this 3 times.
24 3
Output](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffabcd8de-5995-4996-ab40-ec1c9623d1e0%2Fc1b57066-dae4-443f-8d59-4281f4a17188%2Fthfds5d_processed.png&w=3840&q=75)
Transcribed Image Text:> + c
4. Multiple Calls
main.c
by CodeChum Admin
1
#include<stdio.h>
After not being so clear with what I wanted
to ask, Lionel Richie's starting to ignore me.
3 void spam1();
4 void spam2();
I'm usually patient but sometimes, getting
6- int main(void) {
ignored is something I really don't like e
7
8
// TODO: Call spam1() and spam2() here 3 times
Oh, I know! I'll bombard him with a lot of
9.
calls!
10
11
return 0;
12 };
13
Instructions:
14 - void spam1() {
for(int i = 1; i <= 5; i++) {
printf("%d. Respond baaaack\n", i);
}
15 -
1. In the code editor, you are provided
with an empty main() code as well as
two completely defined functions,
spam1() and spam2()
2. In the main(), call these two functions
interchangeably starting with spam1()
and then spam2().
16
17
18 }
19
20 - void spam2() {
for(int i = 1; i <= 5; i++) {
printf("%d. Lionel Richieee\n", i);
}
21-
22
23
3. Do this 3 times.
24 3
Output
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