TITLE DATE C. Will WHy HS be acidic or basic in H₂O? kb of NH3 7 1.76 x 10-5 2 Kai H S = 9 × 10-8 Jad greatest vale is 1.76 × 105 Solution IS basic 2. C₁₂ H18 ONY scle Ka = 3.37 2107 ① Find pH = 3,50 PH = 10-3.5 46= kb= 1,0×10 3.37x107 -14 *- 3.0 x10 + H₂O C→ C₁₂ H₁, UNY SCI₂ -log [H3O+] 3.50 = -log C H₂01 H30 = CH2O = 3,220 Xô Galaxy S21 Ultra 5G SQUARE = i 939 out tion 900 Shoutd 7. Thiamine hydrochloride (C12H18ON4SCI2) is a water soluble form of thiamine (vitamin B1; Ka = 3.37 x 107). How many grams of the hydrochloride must be dissolved in 10.00 mL of water to give a pH of 3.50? C12H18ON4SCl2 + H2O C12H17ON4SCl2 + H3O+ 8. What is the pH of a solution containing 33 g of Na3PO4 per liter? What is the [OH-] of this solution? See necessary Ka values above in problem 1. POU 3- + 7 Н2О = 4ром 2- Kb = kw +04 Ka Und NPO 33 Na Poy 163.74 mil Naz pou IL S -20129 M PO³- Ice The 1.0×10-14 4.2 x10-13 =2.4×10-2 48 | Page V= 10.00μL

Chemistry: An Atoms First Approach
2nd Edition
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Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter13: Acids And Bases
Section: Chapter Questions
Problem 122E: Papaverine hydrochloride (abbreviated papH+Cl; molar mass = 378.85 g/mol) is a drug that belongs to...
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I am not sure how to get kb and I want to see if I am on the right track for this equation ... Number 8
TITLE
DATE
C. Will
WHy HS
be acidic
or basic in H₂O?
kb
of NH3
7 1.76 x 10-5
2
Kai H
S
= 9 × 10-8
Jad
greatest vale
is 1.76 × 105
Solution
IS
basic
2.
C₁₂ H18 ONY scle
Ka = 3.37 2107
①
Find
pH = 3,50
PH
=
10-3.5
46=
kb=
1,0×10
3.37x107
-14
*-
3.0 x10
+ H₂O C→ C₁₂ H₁, UNY SCI₂
-log [H3O+]
3.50
= -log C H₂01
H30
= CH2O = 3,220 Xô
Galaxy S21 Ultra 5G
SQUARE =
i
939
Transcribed Image Text:TITLE DATE C. Will WHy HS be acidic or basic in H₂O? kb of NH3 7 1.76 x 10-5 2 Kai H S = 9 × 10-8 Jad greatest vale is 1.76 × 105 Solution IS basic 2. C₁₂ H18 ONY scle Ka = 3.37 2107 ① Find pH = 3,50 PH = 10-3.5 46= kb= 1,0×10 3.37x107 -14 *- 3.0 x10 + H₂O C→ C₁₂ H₁, UNY SCI₂ -log [H3O+] 3.50 = -log C H₂01 H30 = CH2O = 3,220 Xô Galaxy S21 Ultra 5G SQUARE = i 939
out
tion
900
Shoutd
7. Thiamine hydrochloride (C12H18ON4SCI2) is a water soluble form of thiamine (vitamin B1; Ka =
3.37 x 107). How many grams of the hydrochloride must be dissolved in 10.00 mL of water to
give a pH of 3.50?
C12H18ON4SCl2 + H2O C12H17ON4SCl2 + H3O+
8. What is the pH of a solution containing 33 g of Na3PO4 per liter? What is the [OH-] of this
solution? See necessary Ka values above in problem 1.
POU
3-
+
7
Н2О = 4ром 2-
Kb = kw
+04
Ka
Und NPO
33 Na Poy 163.74 mil Naz pou
IL
S
-20129 M PO³-
Ice The
1.0×10-14
4.2 x10-13
=2.4×10-2
48 | Page
V= 10.00μL
Transcribed Image Text:out tion 900 Shoutd 7. Thiamine hydrochloride (C12H18ON4SCI2) is a water soluble form of thiamine (vitamin B1; Ka = 3.37 x 107). How many grams of the hydrochloride must be dissolved in 10.00 mL of water to give a pH of 3.50? C12H18ON4SCl2 + H2O C12H17ON4SCl2 + H3O+ 8. What is the pH of a solution containing 33 g of Na3PO4 per liter? What is the [OH-] of this solution? See necessary Ka values above in problem 1. POU 3- + 7 Н2О = 4ром 2- Kb = kw +04 Ka Und NPO 33 Na Poy 163.74 mil Naz pou IL S -20129 M PO³- Ice The 1.0×10-14 4.2 x10-13 =2.4×10-2 48 | Page V= 10.00μL
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