Our method of calculating a 95 percent confidence interval for the mean µ of a normal population, with knownvariance o2, is1.9601.960XnXn +This method of creating an interval has the property that a single SRS of size n will provide an interval that willcontaining u with 0.95 probability. If five different individuals select 5 independent samples, each of sizetheir resulting five interval estimates of 4,(i) what is the probability that u will belong to all five of them:(ii) None will contain µ?(iii) What is the probability that at least one of the intervals will contain u?and obtainп,The following``answers" have been proposed.(a) (i) (0.95)5, (ii) (0.95)5, (iii) (0.95)5.(b) (i) (0.05)5, (ii) 1– (0.05)5, (iii) (0.95)5,(c) (i) 1 – (0.05)5, (ii) (0.05)5, (iii) (0.95)5.(d) (i) (0.95)5, (ii) (0.05)5, (iii) 1 – (0.05)5.(e) None of the above.The correct answer is(a)(b)(c)(d)(e)N/A(Select One)

Answered: Image /qna-images/answer/73185e87-92e8-4d27-980b-3baa6633572f.jpg

Answered: Our method of calculating a 95 percent…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Two samples, each with n = 5 scores, have a pooled variance of s 2 p = 40. What is the estimated standard error for the sample mean difference? a. s(M1 - M2) = 10 b. s(M1 - M2) = 20 c. s(M1 - M2) = 4 d. s(M1 - M2) = 8
The results of a state mathematics test for random samples of students taught by two different teachers at the same school are shown below. Can you conclude there is a difference in the mean mathematics test scores for the students of the two teachers? Use α = 0.01. In addition, assume the populations are normally distributed and the population variances/standard deviations are not equal. Teacher 1 Teacher 2 ?̅1 = 473 ?̅2 = 459 S1 = 39.7 S2 = 24.5 n 1 = 8 n 2 = 18 a. State the null and alternate hypotheses (write it mathematically) and write your claim. b. Find the test statistic c. Identify the Rejection region (critical region) and fail to reject region. Show this by drawing a curve and…
Please do the following questions with full handwritten working out. Mean= 0.177911 Variance=0.057632
Suppose we have two normal populations denoted A and B, and we want to compare their population variances by estimating the ratio: variance of population B divided by variance of population A. We have an independent random sample of size 15 from population A and an independent random sample of size 9 from population B. The sample variance for population B turns out to be 30 percent larger than that for population A. What is the 99 percent confidence interval for the ratio: population variance of population B divided by population variance of population A? Use stattrek.org for finding the needed critical values.
In the year 2033, Sarai Patterson is a leading traveling nurse. Sarai is interested in reducing the mean recovery time for patients after experiencing a serious injury (assume recovery times are normally distributed). Suppose the mean recovery time is presently 8.6 months. Sarai takes a random sample of 46 patients that have experienced serious injury to participate in a new treatment program and finds the sample mean is 8.1 months and a sample standard deviation of 1.2 months. Using α = 0.05, answer the following questions. a) What is the setup for your null and alternative hypothesis? b) What is the value of the test statistic? c) What is/are the critical value(s)?
7. What is the 95% confidence interval for the difference in the population means, µ1 - µ2, given the data from the two independent samples: n1 =56, x1= 58.2, s1= 4.3, n2=45, x2=60.2, s2=5.5 B. [-3.28 , -0.72] C. [-3.60, -0.40] D. [-3.65 , -0.35] A. [-3.96 , -0.04] 8. What is the 98% confidence interval for the difference in the population means, µ1 - µ2, given: n1= 22, x1= 41.4, s1= 5.9, n2= 19, x2= 43.2, s2= 6.5 D. [-3.48 , -0.12] B. [-3.07 , -0.53] A. [-3.12, -0.48] C. [-3.18, -0.42]
The weight (in ounces) of a frozen food package produced by a given manufacturer is a normal random variable with mean u and variance o? (both unknown). We weigh n = 10 of these packages, selected at random and independently from those produced by this manufacturer and find 10 10 E*; = 159, E 4 = 2531. i) Estimate the true average weight of all packages produced by this manufacturer using a 95% confidence interval. ii) Find a 95% upper limit confidence interval for u. iii) Determine a 95% confidence interval for the true standard devi- ation, o.
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