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otype number 756 2 723 123 127 = 0.002 = 0.02 = 0.2

otype number 756 2 723 123 127 = 0.002 = 0.02 = 0.2

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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There are a number of ways to calculate linkage disequilibrium (D). We went over one in class. Using the following table of haplotype numbers for two genes (A, and B) with two different alleles per gene (A1,A2, and B1,B2) to calculate |D|. Use a Chi-Square test to determine whether or not these two genes in linkage disequilibrium or linkage equilibrium and interpret. Haplotype number A1B1 756 A1B2 723 A2B1 123 A2B2 127 O D = 0.002 O D = 0.02 D = 0.2 O D is not 0.002, 0.02, or 0.2. O The genes are experiencing LD, there are more A1B1, A1B2 haplotypes than expected. O The genes are experiencing LD, there are fewer A2B1, A2B2 haplotypes than expected. O The genes appear to not be experiencing linkage disequilibrium.
Transcribed Image Text:There are a number of ways to calculate linkage disequilibrium (D). We went over one in class. Using the following table of haplotype numbers for two genes (A, and B) with two different alleles per gene (A1,A2, and B1,B2) to calculate |D|. Use a Chi-Square test to determine whether or not these two genes in linkage disequilibrium or linkage equilibrium and interpret. Haplotype number A1B1 756 A1B2 723 A2B1 123 A2B2 127 O D = 0.002 O D = 0.02 D = 0.2 O D is not 0.002, 0.02, or 0.2. O The genes are experiencing LD, there are more A1B1, A1B2 haplotypes than expected. O The genes are experiencing LD, there are fewer A2B1, A2B2 haplotypes than expected. O The genes appear to not be experiencing linkage disequilibrium.
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