othsq ol poY 5. Some measurements require a different type of measuring device. Notice that some objects to measure than others (particularly round objects). For these objects, it would be advisabl several measurements and obtain an average. What kind of geometric "figure" is a tennis ball? Use the Vernier caliper to do the following: Sphere Diameter 1 = 6.43 cm m? Volume = (Show area and volume calculation all formula and units Area = m³ Diameter 2 = (6 - 355 cm 6.5 cm used %3D you Area : 4 Tr Volu Diameter 3 = 2 Average Diameter = 6.4 cm 128.6796351 %3D To how many decimal places (in cm) can you accurately read the Vernier caliper?_2decim Pla ces

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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5. Some measurements require a different type of measuring device. Notice that some objects are harder
to measure than others (particularly round objects). For these objects, it would be advisable to make
several measurements and obtain an average.
What kind of geometric "figure" is a tennis ball?
Use the Vernier caliper to do the following:
Sphere
Diameter 1 =
6.43 cm
m? Volume =
(Show area and volume calculations, include
all formula and units you used
Area =
3
m
%3D
Diameter 2 = (6. 355 cm
3
6.5 cm
6.4 cm
Volume: r
3.
mArea - 4 TY
Diameter 3 =
%3D
Average Diameter = 6.4 cm 4 . (3.2)-
w bee
ofn scenunte
%3D
lo128.6796351
137. 2582T4
To how many decimal places (in cm) can you accurately read the Vernier caliper?_2decimal
Pla ces
nlal
Transcribed Image Text:5. Some measurements require a different type of measuring device. Notice that some objects are harder to measure than others (particularly round objects). For these objects, it would be advisable to make several measurements and obtain an average. What kind of geometric "figure" is a tennis ball? Use the Vernier caliper to do the following: Sphere Diameter 1 = 6.43 cm m? Volume = (Show area and volume calculations, include all formula and units you used Area = 3 m %3D Diameter 2 = (6. 355 cm 3 6.5 cm 6.4 cm Volume: r 3. mArea - 4 TY Diameter 3 = %3D Average Diameter = 6.4 cm 4 . (3.2)- w bee ofn scenunte %3D lo128.6796351 137. 2582T4 To how many decimal places (in cm) can you accurately read the Vernier caliper?_2decimal Pla ces nlal
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