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ost per serving (in cents) for six high-fiber cereals rated very good and for nine high-fiber cereals rated good by a magazine are shown below. Cereals Rated Very Good 46 49 63 41 19 78 Cereals Rated Good 72 30 53 53 69 43 48 28 54 ombining the cost-per-serving data for high-fiber cereals rated very good and those rated good from above gives the following data set. 46 49 63 41 19 78 72 30 53 53 69 43 48 28 54 (a) Calculate the quartiles and the interquartile range for this combined data set. (b) Calculate the interquartile range for just the cereals rated good. Is this value greater than, less than, or about equal to the interquartile range computed in part (a)? P1 (a) Calculate the quartiles and the interquartile range for this combined data set. he given data are as follows. 46 49 63 41 19 78 72 30 53 53 69 43 48 28 54 egin by arranging the combined data in numerical order, smallest to largest. 9 28 30 41 43 43 46 48 49 53 53 54 63 69 72 78 53 he next step is to locate the median. The median, or middle number, divides the data into two equally sized halves. In other words, 50% of the ata are less than the median and 50% of the data are greater. The number of observations, n, in the data set influences how to find the value f the median. When n is odd, the single middle value is the median. When n is even, the median is the average of the middle two values. For his data set, n is odd v odd , so the median is the single middle value single middle value he median for this data set is 49.73333 49

ost per serving (in cents) for six high-fiber cereals rated very good and for nine high-fiber cereals rated good by a magazine are shown below. Cereals Rated Very Good 46 49 63 41 19 78 Cereals Rated Good 72 30 53 53 69 43 48 28 54 ombining the cost-per-serving data for high-fiber cereals rated very good and those rated good from above gives the following data set. 46 49 63 41 19 78 72 30 53 53 69 43 48 28 54 (a) Calculate the quartiles and the interquartile range for this combined data set. (b) Calculate the interquartile range for just the cereals rated good. Is this value greater than, less than, or about equal to the interquartile range computed in part (a)? P1 (a) Calculate the quartiles and the interquartile range for this combined data set. he given data are as follows. 46 49 63 41 19 78 72 30 53 53 69 43 48 28 54 egin by arranging the combined data in numerical order, smallest to largest. 9 28 30 41 43 43 46 48 49 53 53 54 63 69 72 78 53 he next step is to locate the median. The median, or middle number, divides the data into two equally sized halves. In other words, 50% of the ata are less than the median and 50% of the data are greater. The number of observations, n, in the data set influences how to find the value f the median. When n is odd, the single middle value is the median. When n is even, the median is the average of the middle two values. For his data set, n is odd v odd , so the median is the single middle value single middle value he median for this data set is 49.73333 49

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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ch4 q14

Step 2 The next step is to find the lower and upper quartiles. The lower quartile is the median of the lower half while the upper quartile is the median of the upper half. Recall that 25% of the data are less than the lower quartile while 75% of the data are greater. Similarly, 75% of the data are less than the upper quartile while 25% of the data are greater. Previously we listed the data in order, smallest to largest, and found the median of 49. To find the lower quartile, find the median of the lower half of the data. The lower half consists of all values that sit below the median but not Including the median. The lower half is listed below, and you can verify that n is odd for the lower half which means the median will be the single middle number. 19 28 30 41 43 46 48 Find the lower quartile. To find the upper quartile, find the median of the upper half of the data. The upper half consists of all values that sit above the median but not including the median. The upper half is listed below, and you can verify that n is odd for the upper half which means the median will be the single middle number. 53 53 54 63 69 72 78 Find the upper quartile. The interquartile range is a measure of variability that is resistant to outliers and is found as follows. interquartile range = upper quartile - lower quartile Find the interquartile range.
Transcribed Image Text:Step 2 The next step is to find the lower and upper quartiles. The lower quartile is the median of the lower half while the upper quartile is the median of the upper half. Recall that 25% of the data are less than the lower quartile while 75% of the data are greater. Similarly, 75% of the data are less than the upper quartile while 25% of the data are greater. Previously we listed the data in order, smallest to largest, and found the median of 49. To find the lower quartile, find the median of the lower half of the data. The lower half consists of all values that sit below the median but not Including the median. The lower half is listed below, and you can verify that n is odd for the lower half which means the median will be the single middle number. 19 28 30 41 43 46 48 Find the lower quartile. To find the upper quartile, find the median of the upper half of the data. The upper half consists of all values that sit above the median but not including the median. The upper half is listed below, and you can verify that n is odd for the upper half which means the median will be the single middle number. 53 53 54 63 69 72 78 Find the upper quartile. The interquartile range is a measure of variability that is resistant to outliers and is found as follows. interquartile range = upper quartile - lower quartile Find the interquartile range.
Tutorial Exercise Cost per serving (in cents) for six high-fiber cereals rated very good and for nine high-fiber cereals rated good by a magazine are shown below. Cereals Rated Very Good 49 63 41 19 46 78 Cereals Rated Good 72 30 53 53 69 43 48 28 54 Combining the cost-per-serving data for high-fiber cereals rated very good and those rated good from above gives the following data set. 46 49 63 41 19 78 72 30 53 53 69 43 48 28 54 (a) Calculate the quartiles and the interquartile range for this combined data set. (b) Calculate the interquartile range for just the cereals rated good. Is this value greater than, less than, or about equal to the interquartile range computed in part (a)? Step 1 (a) Calculate the quartiles and the interquartile range for this combined data set. The given data are as follows. 46 49 63 41 19 78 72 30 53 53 69| 43 48 28 54 Begin by arranging the combined data in numerical order, smallest to largest. 19 28 30 41 43 43 46 48 49 53 53 54 63 69 72 78 The next step is to locate the median. The median, or middle number, divides the data into two equally sized halves. In other words, 50% of the data are less than the median and 50% of the data are greater. The number of observations, n, in the data set influences how to find the value of the median. When n is odd, the single middle value is the median. When n is even, the median is the average of the middle two values. For this data set, n is odd odd , so the median is the single middle value single middle value The median for this data set is 49.73333 49
Transcribed Image Text:Tutorial Exercise Cost per serving (in cents) for six high-fiber cereals rated very good and for nine high-fiber cereals rated good by a magazine are shown below. Cereals Rated Very Good 49 63 41 19 46 78 Cereals Rated Good 72 30 53 53 69 43 48 28 54 Combining the cost-per-serving data for high-fiber cereals rated very good and those rated good from above gives the following data set. 46 49 63 41 19 78 72 30 53 53 69 43 48 28 54 (a) Calculate the quartiles and the interquartile range for this combined data set. (b) Calculate the interquartile range for just the cereals rated good. Is this value greater than, less than, or about equal to the interquartile range computed in part (a)? Step 1 (a) Calculate the quartiles and the interquartile range for this combined data set. The given data are as follows. 46 49 63 41 19 78 72 30 53 53 69| 43 48 28 54 Begin by arranging the combined data in numerical order, smallest to largest. 19 28 30 41 43 43 46 48 49 53 53 54 63 69 72 78 The next step is to locate the median. The median, or middle number, divides the data into two equally sized halves. In other words, 50% of the data are less than the median and 50% of the data are greater. The number of observations, n, in the data set influences how to find the value of the median. When n is odd, the single middle value is the median. When n is even, the median is the average of the middle two values. For this data set, n is odd odd , so the median is the single middle value single middle value The median for this data set is 49.73333 49
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