|| The electron beam inside an old television picture tube is 0.40 mm in diameter and carries a current of 50 μA. This electron beam impinges on the inside of the picture tube screen. a. How many electrons strike the screen each second? b. What is the current density in the electron beam? c. The electrons move with a velocity of 4.0 X 107 m/s. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 5.0 mm?

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Chapter1: Units, Trigonometry. And Vectors
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The electron beam inside an old television picture tube is
0.40 mm in diameter and carries a current of 50 µA. This
electron beam impinges on the inside of the picture tube screen.
a. How many electrons strike the screen each second?
b. What is the current density in the electron beam?
c. The electrons move with a velocity of 4.0 × 107 m/s. What
electric field strength is needed to accelerate electrons from
rest to this velocity in a distance of 5.0 mm?
d. Each electron transfers its kinetic energy to the picture tube
screen upon impact. What is the power delivered to the screen
by the electron beam?
Transcribed Image Text:The electron beam inside an old television picture tube is 0.40 mm in diameter and carries a current of 50 µA. This electron beam impinges on the inside of the picture tube screen. a. How many electrons strike the screen each second? b. What is the current density in the electron beam? c. The electrons move with a velocity of 4.0 × 107 m/s. What electric field strength is needed to accelerate electrons from rest to this velocity in a distance of 5.0 mm? d. Each electron transfers its kinetic energy to the picture tube screen upon impact. What is the power delivered to the screen by the electron beam?
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*** Since there are more than three subparts in the given question So, according to the Bartleby guidelines, the first three subparts are answered. To gen an answer for the rest of the questions, you need to post them separately. ***

Given Data,

Diameter of the tube (d)=0.40 mm

Current (I)=50.0 μA

Velocity of the electron(v)=4.0×107 m/s

Distance(x)= 5.0 mm

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