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orm hydrogen ions and cyanide ions, the equilibriu constant at 25°C is 5 x 10-10. What does this tell yo about the position of the equilibrium and the rate c eaching equilibrium?

orm hydrogen ions and cyanide ions, the equilibriu constant at 25°C is 5 x 10-10. What does this tell yo about the position of the equilibrium and the rate c eaching equilibrium?

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 120QRT
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For the reaction of hydrogen cyanide with water to form hydrogen ions and cyanide ions, the equilibrium constant at 25°C is 5 x 10-10. What does this tell you about the position of the equilibrium and the rate of reaching equilibrium? The equilibrium lies toward products and you can tell nothing about the rate. The equilibrium lies toward reactants and the rate is slow. The equilibrium lies toward reactants and you can tell nothing about the rate. There will be significant amounts of both reactants and products in the equilibrium mixture and You can tell nothing about the rate. The equilibrium lies toward products and the rate is fast.
Transcribed Image Text:For the reaction of hydrogen cyanide with water to form hydrogen ions and cyanide ions, the equilibrium constant at 25°C is 5 x 10-10. What does this tell you about the position of the equilibrium and the rate of reaching equilibrium? The equilibrium lies toward products and you can tell nothing about the rate. The equilibrium lies toward reactants and the rate is slow. The equilibrium lies toward reactants and you can tell nothing about the rate. There will be significant amounts of both reactants and products in the equilibrium mixture and You can tell nothing about the rate. The equilibrium lies toward products and the rate is fast.
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