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Order the following functions in increasing order of growth rate (i.e. O(.) classes). log n log log n n! Vlog n 2" 2'og n 1 (3/2)" 1/3 log, 1/logn n 2 log n (log n) (log n)! in n.2" n

Order the following functions in increasing order of growth rate (i.e. O(.) classes). log n log log n n! Vlog n 2" 2'og n 1 (3/2)" 1/3 log, 1/logn n 2 log n (log n) (log n)! in n.2" n

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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This question is answered but I think there are some problems in the answer. It says that n^(1/3) < n^(1/logn) and (3/2)^n < 2^logn but I guess they both are supposed to be inversed. Since n^(1/logn) has the same value for every n, it is constant and it does not supposed to have a growth rate since it is zero.

Can you control and correct every part of the solution?

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https://www.bartleby.com/questions-and-answers/order-the-following-functions-in-increasing-order-of-growth-rate-i.e.-o.-classes.-log-n-log-log-n-n-/b85a39f1-017d-4c04-8553-4d01341429f8

Order the following functions in increasing order of growth rate (i.e. O(.) classes). log n log log n n! Vlog n 2" 2log n (3/ 2)" log²? 2 1/3 1/logn n 2 log n (log n) (log n)! n.2"
Transcribed Image Text:Order the following functions in increasing order of growth rate (i.e. O(.) classes). log n log log n n! Vlog n 2" 2log n (3/ 2)" log²? 2 1/3 1/logn n 2 log n (log n) (log n)! n.2"
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