Consider a composite wall that includes an 8-mm-thick hardwood siding, 40-mm by 130-mm hardwood studs on 0.65-m centers with glass fiberinsulation (paper faced, 28 kg/m³), and a 12-mm layer of gypsum (vermiculite) wall board.- Wood siding- Stud130 mm- Insulation- Wall board40 mmWhat is the thermal resistance associated with a wall that is 2.5 m high by 6.5 m wide (having 10 studs, each 2.5 m high)? Assume surfaces normal to the x-direction are isothermal.

Answered: Image /qna-images/answer/d0b8254b-fd64-43b5-92da-8d01c011057f.jpg

Answered: |Consider a composite wall that…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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To maximize production and minimize pumping costs, crude oil is heated to reduce its viscosity during transportation from a production field. (1) Consider a pipe-in-pipe configuration consisting of concentric steel tubes with an intervening insulating material. The inner tube is used to transport warm crude oil through cold ocean water. The inner steel pipe (k, = 45 W/m-K) has an inside diameter of D₁, 1 = 150 mm and wall thickness t; = 20 mm while the outer steel pipe has an inside diameter of D₁,2 = 250 mm and wall thickness to = 1;. Determine the maximum allowable crude oil temperature to ensure the polyurethane foam insulation (k = 0.055 W/m-K) between the two pipes does not exceed its maximum service temperature of 7p,max = 70°C. The ocean water is at T, = -5°C and provides an external convection heat transfer coefficient of h, = 500 W/m²K. The convection coefficient associated with the flowing crude oil is h; = 450 W/m².K. (2) It is proposed to enhance the performance of the…
2. Clothing made of several thin layers of fabric with trapped air in between, often called ski clothing, is commonly used in cold climates because it is light, fashionable, and a very effective thermal insulator. So it is no surprise that such clothing has largely replaced thick and heavy old- fashioned coats. Multilayered ski jacket REBUT
Thermal energy is being transferred through a 0.8 mm layer of human skin at a rate of 1.1 x 104 W/m?. The room temperature is 27 °C. (a) Determine the thermal conductivity of the skin.
To reduce heat flux, the skin is wrapped with a clothing material. What should be the thickness of the clothing material covering the surface of this skin tissue to reduce the heat flux to half of its original value? What is the temperature at the skin-clothing material interface? Note: if you think you need to have more information to solve this problem, you're free to make assumptions. Please state them clearly in your answer, if you need to make such assumptions.
Answer correctly and quickly as possible please.
Bebang owns a 830-mm-thick concrete brick table top that has an area of 10,000,000 mm^2 and a 0.750-cm-thick glass plate that has an area of 20,000 cm^2. Assuming the same temperature difference across each, what is the ratio of the rate of heat conduction through the plate with respect to the rate of heat conduction through the table top? Use Table 10.1(given below) for the value of Thermal Conductivity k. Table 10.1 Thermat Conductivities of Common Substances Values are given for temperatures near o °C. Substance Thermal Conductivity k (W/m-O Diamond 2000 Silver 420 Copper 390 Gold 318 Aluminum 220 Steel iron Steel (stainless) 14 Ice 2.2 Glass (average) 0.84 Concrete brick O.84 water 0.6 Fatty tissue (without blood) 0.2 Asbestos 0.16 Plasterboard 0.16 wood 0.08-0.16 Snow (dry) 0.10 Cork 0.042 Glass wool 0.042 wool 0.04 Down feathers 0.025 Air 0.023 Polystyrene foam 0.010
brick and 1. An outside wall for a building consists of a 10-cm (k=0.69 W/m-C) layer of common a 2.5 cm layer of fiber glass (k= 0.05 W/m-C). Calculate the heat flow through the wall for 25 C temperature differential.. 10 cm 2.5cm
A house has a composite wall of wood, fiberglass insulation and plaster board, as indicated in Figure 2.1. The total wall surface area is 300 m²" h = 30 W/m°K Tni = 20°C | h. = 60 W/m²K Teo =-15°C Fiberglass L=10 cm Plaster board k= 0.04 W/mK L=1 cm k = 0.15 W/mK Plywood L-2 cm k= 0.13 W/mK Figure 2.1 (i) Represent the composite wall by a thermal circuit, and label all the components in the circuit ii) Determine the inner surface temperature of the house.
Problem 1 A hot water pipe is used for domestic applications is insulated with a layer of calcium silicate. If the insulation is 25 mm thick and its inner and outer surfaces are maintained at Ts,1 = 800 K and Ts,2 = 400 K, respectively. The outside diameter is 0.12 m. Given the thermal conductivity calcium silicate insulation equals to 0.09 W/m.K. A. Define the difference between lagged and unlagged pipes. B. Calculate the heat loss per unit length for this pipe.
Compute the heat transfer through the composite wall as shown in the Figure below. Consider materials of your choice from table below. Use both methods, thermal conductivity & thermal resistivity.
Please good handwriting and clear ideas explaining the process! a) Calculate the equilibrium temperature inside the submarine
100 mm 50 mm 100 mm Tin T out Figure 3 illustrates a compound wall constructed of an inner and outer layer of standard brick and a central layer of standard cavity wall insulation material. If the temperature inside is 21°C and the temperature outside -3°C, what is the rate of heat transfer through the wall per unit area? Data: take the value of the convective heat transfer coefficient for both inside and outside in (c) as 10 Wm?K

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