This is microprocessor using assembly language 8086 I already have the solution but i don't understand how it works please can you describe to me step by step AXBXCXDXBX+DIDSАНALBHBLCHCLDHDL1000MOV DS, 2000HMOV DX, [0050H]MOV CX,(0052H]ADD DX,CX10003***1300FB***2400FEMOV BX,DXMOV AL,00MOV DS,3000HC: ADD AL,[BX + DI]00FE6.007801100***39.INC BX00 FF10INC CLFC11JNZ C1204101***413*** Physical010014Addresses:FD151000:005009102***51610000+5001011710050FE1821005210103***619010220310100FF2141010119104***7225101020103236.10103002410104Illegal 1. Interpret and execute the instructions and write down the program's outcomesMainMemorya. Assume the DI = 0002H and DS = 1000H when you access the memory, fill the effected registers after executionof each instruction and state the main goal of the program piven below30109 3730108 221530106 OD0805Y개3010730105301043010303AXBXCXDXBX+DIDS301020230101 0130100 01AH ALBHBLCH CLCLDHDL1000MOV DS,2000H20109122***1MOV DX,(0050H)MOV CX,[0052H]000300 FB0020108 1020107 DE20106 OC3***24ADD DX,CXFE5MOV BX,DX00FE20105OA20104080620102 0420101 0220100 006.MOV AL,000020103MOV DS,3000HC: ADD AL,[Bx + DI]8910111201100***3INC BX00FFINC CLFCUNZ C20059000320057 Os20056 0704101***42005813**Physical010014Addresses:FD2005509151000:00500910220054OB1610000+50010120053 OD17110050FE20052OF1821005210103***6200511119010220050 132010100FF214.101011910410109131010811OF10106 OD10105 082210102010310107236.1010300247.10104OB

Answered: or using assembly language 8086 I…

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Computer Science

or using assembly language 8086 I already have the solution but i don't understand how it works please can you describe

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Fundamentals of hardware concepts

A computer system is made of a combination of hardware and software. The software consists of a set of instructions that instruct the computer to perform a task. It can be system software or application software. Whereas, hardware is the part of a computer that can be touched. In other words, computer hardware consists of the physical components of a computer. The internal parts of a computer are called components and the external hardware components are called peripherals.

Question

This is microprocessor using assembly language 8086 I already have the solution but i don't understand how it works please can you describe to me step by step

AX
BX
CX
DX
BX+DI
DS
АН
AL
BH
BL
CH
CL
DH
DL
1000
MOV DS, 2000H
MOV DX, [0050H]
MOV CX,(0052H]
ADD DX,CX
1
00
03
***1
3
00
FB
***2
4
00
FE
MOV BX,DX
MOV AL,00
MOV DS,3000H
C: ADD AL,[BX + DI]
00
FE
6.
00
7
8
01
100
***3
9.
INC BX
00 FF
10
INC CL
FC
11
JNZ C
12
04
101
***4
13
*** Physical
01
00
14
Addresses:
FD
15
1000:0050
09
102
***5
16
10000+50
01
01
17
10050
FE
18
2
10052
10
103
***6
19
01
02
20
3
10100
FF
21
4
10101
19
104
***7
22
5
10102
01
03
23
6.
10103
00
24
10104
Illegal

1. Interpret and execute the instructions and write down the program's outcomes
Main
Memory
a. Assume the DI = 0002H and DS = 1000H when you access the memory, fill the effected registers after execution
of each instruction and state the main goal of the program piven below
30109 37
30108 22
15
30106 OD
08
05
Y
개
30107
30105
30104
30103
03
AX
BX
CX
DX
BX+DI
DS
30102
02
30101 01
30100 01
AH AL
BH
BL
CH CL
CL
DH
DL
1000
MOV DS,2000H
20109
12
2
***1
MOV DX,(0050H)
MOV CX,[0052H]
00
03
00 FB
00
20108 10
20107 DE
20106 OC
3
***2
4
ADD DX,CX
FE
5
MOV BX,DX
00
FE
20105
OA
20104
08
06
20102 04
20101 02
20100 00
6.
MOV AL,00
00
20103
MOV DS,3000H
C: ADD AL,[Bx + DI]
8
9
10
11
12
01
100
***3
INC BX
00
FF
INC CL
FC
UNZ C
20059
00
03
20057 Os
20056 07
04
101
***4
20058
13
**Physical
01
00
14
Addresses:
FD
20055
09
15
1000:0050
09
102
20054
OB
16
10000+50
01
01
20053 OD
17
1
10050
FE
20052
OF
18
2
10052
10
103
***6
20051
11
19
01
02
20050 13
20
10100
FF
21
4.
10101
19
104
10109
13
10108
11
OF
10106 OD
10105 08
22
10102
01
03
10107
23
6.
10103
00
24
7.
10104
OB

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