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| the mistake system of 3 variable equations and asked to solve it. step by step, and even includes the thoughts that lue font). Your job is to find the mistakes that this ations by elimination, each person has many choices to ons..."Which variable will I choose to eliminate first?" " and the questions and choices go on.. Be sure to pu may have made a different one. The student is t's work and find the mistakes. There are three hat is made and explain what was done incorrectly. problem. Just highlight each mistake and then ke was made and seek to find another error (or ter looking over this problem, I am going to call the first ation A; the second equation B, and the third equation C. I choose to first eliminate z. d multiplying B by 3. 6 ogether, I will get the following equation for D:

| the mistake system of 3 variable equations and asked to solve it. step by step, and even includes the thoughts that lue font). Your job is to find the mistakes that this ations by elimination, each person has many choices to ons..."Which variable will I choose to eliminate first?" " and the questions and choices go on.. Be sure to pu may have made a different one. The student is t's work and find the mistakes. There are three hat is made and explain what was done incorrectly. problem. Just highlight each mistake and then ke was made and seek to find another error (or ter looking over this problem, I am going to call the first ation A; the second equation B, and the third equation C. I choose to first eliminate z. d multiplying B by 3. 6 ogether, I will get the following equation for D:

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Find the mistake In the problem below, a student is given a system of 3 variable equations and asked to solve it. The student has written out the solution, step by step, and even includes the thoughts that crossed over his/her mind (presented in blue font). Your job is to find the mistakes that this student makes. When solving a system of 3 variable equations by elimination, each person has many choices to make and can choose many different options...."Which variable will I choose to eliminate first?" "Which two equations will I add together?" and the questions and choices go on.... Be sure to find MISTAKES not just choices where you may have made a different one. The student is making the choices. Follow this student's work and find the mistakes. There are three mistakes total. Highlight the mistake that is made and explain what was done incorrectly. You do NOT need to fix and finish the problem. Just highlight each mistake and then follow their work, even after the mistake was made and seek to find another error (or two). Problem: 3x + 2y – 3z = – 2 2x - 5y + 2z = - 2 1)After looking over this problem, I am going to call the first equation A; the second equation B, and the third equation C. I choose to first eliminate z. 4x – 3y + 4z = 10 2) So, I will start by multiplying A by 2 and multiplying B by 3. 2(3x + 2y – 3z = - 2) = 6x+ 4y – 6z = - 4 3(2х - 5y + 2: %3D - 2) %3D бх — 15у + 62 3D 3) Now when I add these two equations together, I ill get the following equation for D: 12x - 1ly = - 10 The z terms drop out! 4) Now, I need to add C with A. To get z to drop out again, I will need to multiply A by 4 and C by 3. 4(3x + 2y – 3z = - 2) = 12x + 8y – 12z = -8 3(4x - 3y + 4z = 10) = 12x – 9y + 12z = 30 5) Now, when I add A and C together (after multiplying), the z will drop out. Here is what I get for E: 24x+ y = 22 6) Now, I look over D and E (two equations in which z has been removed), and I decide to get rid of the x variable next. D: 12x - 11y = - 10
Transcribed Image Text:Find the mistake In the problem below, a student is given a system of 3 variable equations and asked to solve it. The student has written out the solution, step by step, and even includes the thoughts that crossed over his/her mind (presented in blue font). Your job is to find the mistakes that this student makes. When solving a system of 3 variable equations by elimination, each person has many choices to make and can choose many different options...."Which variable will I choose to eliminate first?" "Which two equations will I add together?" and the questions and choices go on.... Be sure to find MISTAKES not just choices where you may have made a different one. The student is making the choices. Follow this student's work and find the mistakes. There are three mistakes total. Highlight the mistake that is made and explain what was done incorrectly. You do NOT need to fix and finish the problem. Just highlight each mistake and then follow their work, even after the mistake was made and seek to find another error (or two). Problem: 3x + 2y – 3z = – 2 2x - 5y + 2z = - 2 1)After looking over this problem, I am going to call the first equation A; the second equation B, and the third equation C. I choose to first eliminate z. 4x – 3y + 4z = 10 2) So, I will start by multiplying A by 2 and multiplying B by 3. 2(3x + 2y – 3z = - 2) = 6x+ 4y – 6z = - 4 3(2х - 5y + 2: %3D - 2) %3D бх — 15у + 62 3D 3) Now when I add these two equations together, I ill get the following equation for D: 12x - 1ly = - 10 The z terms drop out! 4) Now, I need to add C with A. To get z to drop out again, I will need to multiply A by 4 and C by 3. 4(3x + 2y – 3z = - 2) = 12x + 8y – 12z = -8 3(4x - 3y + 4z = 10) = 12x – 9y + 12z = 30 5) Now, when I add A and C together (after multiplying), the z will drop out. Here is what I get for E: 24x+ y = 22 6) Now, I look over D and E (two equations in which z has been removed), and I decide to get rid of the x variable next. D: 12x - 11y = - 10
E: 24x +y = 22 7) So, I will multiply D by -2 - 2(12x – 11y = – 10) = - 24x - 22y = 20 8) Now, when I add D (multiplied by -2) and E, the x's drop out and here is what I am left with: - 21y = 42 9) Now, I can solve for y by dividing both sides by -21. y = - 2 10) To find the value of x, I can plug -2 in for y to either equation D or E. I will choose equation D: 12x - 1ly = - 10 12x – 11(- 2) = - 10 12x + 22 = - 10 12x = 12 x = 1 11) Now, that I know what x and y are, I can plug those two values into one of my original equations (A, B, or C). I will choose B: 2x - 5y + 2z = -2 I will plug in 1 for x and -2 for y. 2x – 5y + 2z = - 2 2(1) - 5(- 2) + 2z = -2 2+ 10 + 2z = - 2 12 + 2z = -2 2z = - 14 := - 7 12) My final answer is (1,-2,-7)
Transcribed Image Text:E: 24x +y = 22 7) So, I will multiply D by -2 - 2(12x – 11y = – 10) = - 24x - 22y = 20 8) Now, when I add D (multiplied by -2) and E, the x's drop out and here is what I am left with: - 21y = 42 9) Now, I can solve for y by dividing both sides by -21. y = - 2 10) To find the value of x, I can plug -2 in for y to either equation D or E. I will choose equation D: 12x - 1ly = - 10 12x – 11(- 2) = - 10 12x + 22 = - 10 12x = 12 x = 1 11) Now, that I know what x and y are, I can plug those two values into one of my original equations (A, B, or C). I will choose B: 2x - 5y + 2z = -2 I will plug in 1 for x and -2 for y. 2x – 5y + 2z = - 2 2(1) - 5(- 2) + 2z = -2 2+ 10 + 2z = - 2 12 + 2z = -2 2z = - 14 := - 7 12) My final answer is (1,-2,-7)
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