or Questions 11-16: Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question. ??2?−27(??)+???2(??)⟶??+3(??)+??−3(??)Cr2O7−2(aq)+HNO2(aq)⟶Cr+3(aq)+NO3−(aq) Step 5: Make the number of electrons in each half reaction equal by finding the multiplying factor for each half reaction {Cr2O7-2(aq) + 14H+ (aq) +6e- ⟶⟶ 2Cr+3(aq) + 7 H2O (l) } x ["", "", "", ""] {HNO2(aq) + H2O (l) + ⟶⟶ NO3-(aq) + 3H+ (aq) + 2e- } x
or Questions 11-16: Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question. ??2?−27(??)+???2(??)⟶??+3(??)+??−3(??)Cr2O7−2(aq)+HNO2(aq)⟶Cr+3(aq)+NO3−(aq) Step 5: Make the number of electrons in each half reaction equal by finding the multiplying factor for each half reaction {Cr2O7-2(aq) + 14H+ (aq) +6e- ⟶⟶ 2Cr+3(aq) + 7 H2O (l) } x ["", "", "", ""] {HNO2(aq) + H2O (l) + ⟶⟶ NO3-(aq) + 3H+ (aq) + 2e- } x
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter6: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 90E: Balance each of the following oxidationreduction reactions by nsing the oxidation states method. a....
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For Questions 11-16:
Balance the following
??2?−27(??)+???2(??)⟶??+3(??)+??−3(??)Cr2O7−2(aq)+HNO2(aq)⟶Cr+3(aq)+NO3−(aq)
Step 5: Make the number of electrons in each half reaction equal by finding the multiplying factor for each half reaction
{Cr2O7-2(aq) + 14H+ (aq) +6e- ⟶⟶ 2Cr+3(aq) + 7 H2O (l) } x ["", "", "", ""]
{HNO2(aq) + H2O (l) + ⟶⟶ NO3-(aq) + 3H+ (aq) + 2e- } x
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