or H0: 2 44, if a sample gave mean value of 50 with confidence interval (CI) of 4 53. It can be concluded that there is to reject HO cause fficient, the upper limit of the CI is higher than 50 fficient, the lower limit of the CI is lower than 50 ufficient, the upper limit of the CI is lower than 50 ficient, the lower limit of the CI is higher than 44 fficient, the upper limit of the CI is higher than 44
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- Suppose 20 Pennsylvania high school cross-country runners participated in a 5 K race. The mean finish time was 1400 seconds (23 minutes, `20 seconds) with a standard deviation of 60 seconds. Assuming the 20 race times are representative of times for all experienced 5 K runners in this age group and 5 K race times are approximately normally distributed, find the LOWER bound of a 90% confidence interval for the 5 K race times for Pennsylvania high school cross-country runners. For your answer, round to whole seconds, (i.e. 1234), and only the lower bound is requested, (not the entire lower and upper interval).a data set includes 109 body temperatures of healthy adult humans having a mean of 98.3 f and a standarddeviationn of 0.54F construct a 99% confidence interval estimate of the human body temperature of all healthy humans. What does the sample suggest about the use of 98.6 F as the mean body temperature?The wear resistances of two types of automobile tires were compared on road test samples of n1 = n2 = 100 tires for each type and the number of miles traveled to deterioration, defined as a specific amount of tire wear, was recorded. tire. The test results are shown in the table. Estimate (mu subscript 1 minus mu subscript 2), the difference in the mean miles to complete wear, using a 99% confidence interval. Is there a difference in the average wear quality for the two types of tires? summary of sample data for two types of tires rim 1: x1 = 26400 miles s1 ^ 2 = 1,440.00 Rim 2: x2 = 25,100 miles s2 ^ 2 = 1,960,000
- A toy manufacturer wants to see how long, on average, a new toy captures children's attention. He tests 17 children selected at random and finds that their mean attention span is 21 minutes with a standard deviation of 6 minutes. If we assume that attention spans are normally distributed, find a 90% confidence interval for the mean attention span of children playing with this new toy. Then find the lower limit and upper limit of the 90% confidence interval. pur re Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) |Lower limit: Upper limit: Save For Later Submit Assignment Continue ORgbts Roservod. Terms of Use Privacy Center Accessiblity acer backspa esc & # $ % 8 9. @ 7 4 5 2 3 t y W e tabIf we increase the sample size of SRS’s, then the width of the confidence intervals (CI’s) becomes which of the following: (i) wider (ii) stays the same (iii) narrowerST5
- What is the lower and upper boundary for a 95% confidence interval for the difference between the mean number of accidents on the two dates? Please make sure to use exact values in calculation and round final answer to 4 decimal places!!A candle company wishes to estimate the time it takes their candles to completely burn. They choose 23 candles at random from their latest production run and measure how long each takes to burn. The average time of this sample is 264 minutes with a standard deviation of 25 minutes. If the company uses a 99% confidence interval to measure the average burn time of all candles in this production run, what will their margin of error be? please show work!In a production process of metal sticks, the length of these metal sticks is distributed normal with standard deviation of 1.8 millimeter. A random sample of 9 metal sticks are chosen and 99 percent confidence interval is computed with lower and upper bounds of 194.65 and 197.75. The production engineer finds that these bounds are not useful. Instead he wants that these bounds should be 0.50 millimeter larger and less on both sides of the mean with 99 percent confidence interval. Compute the necessary sample size for engineer’s specification.
- If n=270 and p' (p-prime) = 0.42, construct a 90% confidence interval. Give your answers to three decimals. Next Question hpA random sample of 100 accounts from a branch of certain bank, has mean balance of Rs. 18,600 with S.D.= 1160. A random sample of 80 accounts from another branch of same bank has mean balance of Rs. 15,200; with S.D.= Rs. 920. Find 90% confidence interval of difference between Mean balance of all accounts in both branches.A random sample of 64 students at a university showed an average age of 25 years and a sample standard deviation of 2 years. The 98 % confidence interval for the true average age of all students in the university is * 20.5 to 29.5. O24.4 to 25.6. 23.0 to 27.0. O 20.0 to 30.0.