BI S AL Y - -100%% .0 .00 123-Default (Ari. - 10A1- fx |ABDFGH1O(1)O(log n)O(n)O(n)O(n^2)Instructions:nT(n) = 100T(n) = log2 n + 100T(n) = 3n + 400T(n) = 10nT(n) = n^2 - 100n + 22* You are not to modify the given values in the table!* log2 n ==> is to be read as log of n, base 231004200* n^2 ==> is to be read as n raised to the power of 2300Tasks to be done:64001Determine the values for the given time complexity functions with the given500n values (100 to 1000).78.600Note: You may issue formulas to easily fill out the needed values in the table.7002 What generalizations can you derive from the values that you were able to10800generate?Place your answer below:119001210001314151617181920212223242526272829

The question is on: determining the values of given time complexity functions given in the excel…

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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implement greatestBitPos function Compute a mask marking the most significant 1 bit. you are only allowed to use the following eight operators: ! ~ & ^ | + << >> “Max ops” field gives the maximum number of operators you are allowed to use to implement each function /* * greatestBitPos - return a mask that marks the position of the* most significant 1 bit. If x == 0, return 0* Example: greatestBitPos(96) = 0x40* Legal ops: ! ~ & ^ | + << >>* Max ops: 70* Rating: 4 */int greatestBitPos(int x) {return 2;}
Let f(n)= 3 T(n/3) + O(n log n). Then f(n) is O e(n² log? n) e(n² log? n) O en log n) O ein? log n) Let T(n)= 25T(n/5) + O(n). Then O on) O T(n) = O(n³) O T(n) = O(1) O T(n) = O(n) O Tin) = O(n²) none of the cases is correct
2. Explain why the timing function cannot be derived in the first question when n is not equal to an integer power of 2 and n > 1.
Python Programming
Find output of following code. If there is an error in code, make it correct and write the output mov ax, 20 mov bx, 0 subtraction: sub ax, [num1+bx] add bx, 2 cmp bx, 6 jne subtraction num1: dw 2, 1, 4, 1, 2
Kindly asnwer ASAP
Assume that: int x[5] = {2,4,5,7,8}; What are the values of x after calling: swap(x+2, x+4); swap(x+1, x+3); if the swap function is defined as follows void swap(int *a, int *b) { int t; t=*b; *b=*a; *a=t;} Select one: O a. {2,7,5,4,8} O b. {2,4,5,7,5} O c. {2,4,5,4,5} O d. {2,7,8,4,5}
Use Python Write a function, say_spam(n); it takes an integer parameter n and prints "Spam!" n times in response. You should assume n > 0 for this function. Hint: Use a simple for loop with a print statement in the body of the loop. For example: Test Input Result say_spam(1) Spam! say_spam(2) say_hello(3) Spam! Spam! say_spam(5) Spam! Spam! Spam! Spam! Spam!
explain every line in phytone code in colab below pls: # f(x) = tanx, f'(x) = 1 / cosx^2, f'(1), f'(2), f'(3)=? # h interval: 1/100 - 1/1000 from math import * def f(x): return tan(x) def f1(x): return 1/cos(x)**2 h = 0.001 print ("F1 Forward ", "F1 Back ", "F1 Simetric ", "F1 Exact ") for i in range (3): x = float(i+1) f1_forward = (f(x+h)-f(x))/h f1_back = (f(x)-f(x-h))/h f1_simetric = (f(x+h)-f(x-h))/(2*h) f1_exact = f1(x) print ("%.10f" %f1_forward, "%.10f" %f1_back, "%.10f" %f1_simetric, "%.10f" %f1_exact)
Please make a Python code which can generate a multiplication table given input n.
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