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or each function.m 6. P(-2)=x4 + 3x³+x²+x+3 7. P(3)=2x³+4x²-x-9; 8. P 9. P(1) -- 4 P(3)=2x³ + x²-x-9; 10. P 2 5 |=-16x³-x² - 5x-4rt bomilo off = 10x4 + x³ - 12x² + 15x-4

or each function.m 6. P(-2)=x4 + 3x³+x²+x+3 7. P(3)=2x³+4x²-x-9; 8. P 9. P(1) -- 4 P(3)=2x³ + x²-x-9; 10. P 2 5 |=-16x³-x² - 5x-4rt bomilo off = 10x4 + x³ - 12x² + 15x-4

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Answer 6-10
Practice and Application I. Use the synthetic substitution to find P(x) for each function. P(3)=x²-3x²-x+ 2x³ 2. P 3. P(2 - 4x + 1 2- 8x + 7 +5 =x³-8x 5. P(1) = 5x + 7x² - 1 #i 6. P(-2)=x+3x³+x²+x+3 7. P(3)=2x³+4x² - x - 9; 8. P P(+) 9. P(3) = 2x³ + x²-x-9; (3) 10. P = -16x³x² - 5x - 4 = 10x4 + x³-12x² + 15x - 4
Transcribed Image Text:Practice and Application I. Use the synthetic substitution to find P(x) for each function. P(3)=x²-3x²-x+ 2x³ 2. P 3. P(2 - 4x + 1 2- 8x + 7 +5 =x³-8x 5. P(1) = 5x + 7x² - 1 #i 6. P(-2)=x+3x³+x²+x+3 7. P(3)=2x³+4x² - x - 9; 8. P P(+) 9. P(3) = 2x³ + x²-x-9; (3) 10. P = -16x³x² - 5x - 4 = 10x4 + x³-12x² + 15x - 4
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