H.W.5: Determine i, i,, and v, for all t in the circuit shown in Fig.. Assume that the switchwas closed for a long time. It should be noted that opening a switch in series with an idealcurrent source creates an infinite voltage at the current source terminals. Clearly this isimpossible. For the purposes of problem solving, we can place a shunt resistor in parallelwith the source (which now makes it a voltage source in series with a resistor). In morepractical circuits, devices that act like current sources are, for the most part, electroniccircuits. These circuits will allow the source to act like an ideal current source over itsoperating range but voltage-limit it when the load resistor becomes too large (as in an opencircuit).(12At<0tく0(24Vtく0(6A1-4e-24A t> 0'Answer: i =12e-24A t2 0'"al8e-2'v t>0t= 01 H18 AFig.wwww

Answered: Image /qna-images/answer/5789ce02-0a4c-4e6a-accf-4b26f07f9610.jpg

Answered: | circuit). (12A 12e-24A t20' t<0 (6A…

Engineering

Electrical Engineering

| circuit). (12A 12e-24A t20' t<0 (6A 1-4e-24A t>0' (24V t<0 Answer: i = v, = l8e-2tv t>0 ww 1 H 18 A 42 Fig. ww 2.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Norton Theorem

In the current circuit law, the Norton theorem (also known as the Mayer-Norton theorem) is a simplification that can be applied to networks generated by a constant line of opposition, power sources, and current assets. In two network terminals, it can be switched on with a current supply and single resistor respectively.

Question

H.W.5: Determine i, i,, and v, for all t in the circuit shown in Fig.. Assume that the switch
was closed for a long time. It should be noted that opening a switch in series with an ideal
current source creates an infinite voltage at the current source terminals. Clearly this is
impossible. For the purposes of problem solving, we can place a shunt resistor in parallel
with the source (which now makes it a voltage source in series with a resistor). In more
practical circuits, devices that act like current sources are, for the most part, electronic
circuits. These circuits will allow the source to act like an ideal current source over its
operating range but voltage-limit it when the load resistor becomes too large (as in an open
circuit).
(12A
t<0
tく0
(24V
tく0
(6A
1-4e-24A t> 0'
Answer: i =
12e-24A t2 0'
"a
l8e-2'v t>0
t= 0
1 H
18 A
Fig.
ww
ww

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