Optimizartion 5) Find the avea of the largest rectangle an be inscribed in a right triangle with lee lenytns 4cm and 5 cm' it two sides of th lie along the legs

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Optimization Problem

**Problem Statement:**
5. *Find the area of the largest rectangle that can be inscribed in a right triangle with legs of lengths 4 cm and 5 cm if two sides of the rectangle lie along the legs.*

**Solution Steps:**
1. **Define the Variables:**
    - Let the lengths of the legs of the right triangle be \(a = 4 \text{ cm}\) and \(b = 5 \text{ cm}\).
    - Let the dimensions of the rectangle be \(x \text{ cm}\) and \(y \text{ cm}\).

2. **Determine the Relationship between \(x\) and \(y\):**
    - Because the right triangle has legs of lengths 4 cm and 5 cm, the relationship between \(x\) and \(y\) is given by the equation \( \frac{x}{a} + \frac{y}{b} = 1 \).

3. **Formulate the Area Function to be Maximized:**
    - The area \(A\) of the rectangle is given by \(A = xy\).

4. **Substitute \(y\) in terms of \(x\) into the Area Function:**
    - Using the relationship \( \frac{x}{4} + \frac{y}{5} = 1 \) to express \(y\) in terms of \(x\), we get:
        \[
        y = 5 \left(1 - \frac{x}{4}\right) = 5 - \frac{5x}{4}.
        \]
    - Substitute \(y\) into the area function:
        \[
        A = x \left(5 - \frac{5x}{4}\right) = 5x - \frac{5x^2}{4}.
        \]

5. **Differentiate the Area Function to Find Maximum Area:**
    - Differentiate \(A\) with respect to \(x\):
        \[
        \frac{dA}{dx} = 5 - \frac{5x}{2}.
        \]
    - Set the derivative equal to zero to find the critical points:
        \[
        5 - \frac{5x}{2} = 0 \implies x = 2.
        \]

6. **Determine the Corresponding \(y\) Value:**
    - Substitute \(x
Transcribed Image Text:### Optimization Problem **Problem Statement:** 5. *Find the area of the largest rectangle that can be inscribed in a right triangle with legs of lengths 4 cm and 5 cm if two sides of the rectangle lie along the legs.* **Solution Steps:** 1. **Define the Variables:** - Let the lengths of the legs of the right triangle be \(a = 4 \text{ cm}\) and \(b = 5 \text{ cm}\). - Let the dimensions of the rectangle be \(x \text{ cm}\) and \(y \text{ cm}\). 2. **Determine the Relationship between \(x\) and \(y\):** - Because the right triangle has legs of lengths 4 cm and 5 cm, the relationship between \(x\) and \(y\) is given by the equation \( \frac{x}{a} + \frac{y}{b} = 1 \). 3. **Formulate the Area Function to be Maximized:** - The area \(A\) of the rectangle is given by \(A = xy\). 4. **Substitute \(y\) in terms of \(x\) into the Area Function:** - Using the relationship \( \frac{x}{4} + \frac{y}{5} = 1 \) to express \(y\) in terms of \(x\), we get: \[ y = 5 \left(1 - \frac{x}{4}\right) = 5 - \frac{5x}{4}. \] - Substitute \(y\) into the area function: \[ A = x \left(5 - \frac{5x}{4}\right) = 5x - \frac{5x^2}{4}. \] 5. **Differentiate the Area Function to Find Maximum Area:** - Differentiate \(A\) with respect to \(x\): \[ \frac{dA}{dx} = 5 - \frac{5x}{2}. \] - Set the derivative equal to zero to find the critical points: \[ 5 - \frac{5x}{2} = 0 \implies x = 2. \] 6. **Determine the Corresponding \(y\) Value:** - Substitute \(x
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