Optical rotation power of a quartz crystal plate is 8 = 21.7°/mm for a sodium yellow light (2 =589.3 nm). When placing this crystal plate between two linear polarizers in which the transmittedaxes are perpendicular (aintensity, compute (a) the minimum thickness of the crystal plate (1) and (b) refractive indexdifference of the right and left circularly polarized light (An = ng – n1).90°). In order to make the transmitted light have the maximum

Given δ = 21.7°/mm λ = 589.3 nm = 589.3×10-9 m α = 90° Find, the l and ∆n =nR-nL, a following below.

Optical rotation power of a quartz crystal plate is 8 = 21.7 /mm for a sodium yellow light (1 = 589.3 nm). When placing this crystal plate between two linear polarizers in which the transmitted axes are perpendicular (a = 90°). In order to make the transmitted light have the maximum intensity, compute (a) the minimum thickness of the crystal plate (1) and (b) refractive index difference of the right and left circularly polarized light (An = ng – n1).

Optical rotation power of a quartz crystal plate is 8 = 21.7 /mm for a sodium yellow light (1 = 589.3 nm). When placing this crystal plate between two linear polarizers in which the transmitted axes are perpendicular (a = 90°). In order to make the transmitted light have the maximum intensity, compute (a) the minimum thickness of the crystal plate (1) and (b) refractive index difference of the right and left circularly polarized light (An = ng – n1).