Optic axis Plant Lens
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Figure shows a small plant near a thin lens. The ray shown is one of the principal rays for the lens. Each square is 2.0 cm along the horizontal direction, but the vertical direction is not to the same scale. Use information from the diagram for the following: (a) Using only the ray shown, decide what type of lens (converging or diverging) this is. (b) What is the focal length of the lens? (c) Locate the image by drawing the other two principal rays. (d) Calculate where the image should be, and compare this result with the graphical solution in part (c).
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- Case 7: Consider the case of an object (draw yourself on the diagram, an arrow erect on the optical axis) located at d0 > 2F'. Draw the following rays in the figure: ray parallel to the optical axis, focal ray, central ray, draw the image of the arrow, indicate in the same figure from where to where di is (image-lens distance). Don't forget to put the direction on each ray, both the incident rays and the transmitted rays. Image characteristics for case 7: object located at d0 > 2F'. Choose the ones that apply: a) Virtual b) Real c) Inverted d) Increased e) No image is formed f) Equal size g) Reduced h) Erect Case 10: Consider the case of an object (draw yourself on the diagram, an arrow erect on the optical axis) located within the focus F', that is do < F'. Draw the following rays in the figure: ray parallel to the optical axis, focal ray, central ray, draw the image of the arrow, indicate in the same figure from where to where di is (image-lens distance). Don't forget to…A 40cm tall trolley is placed at u cm from a mirror. The image formed by the mirror is an upright image with the height of its image is 80cm. State the type of mirror and Identify the characteristic of the image. Explain your answer. Given the radius of curvature of the mirror is 40cm, by applying conventional method, prove that the ratio of image distance, v to object distance, u is 1 Should the objct were changed to double the height? If yes/no. Explain the changes happened. Justify your answer.Please answer this within 30 minutes.I will upvote! A concave mirror is used to reflect light from an object placed 6 cm in front of the mirror. The focal length of themirror is 42 cm. Find the location of the image and the magnification by using calculations and draw the ray diagramby using two defined rays Please make sure to draw the ray diagram too please!
- Please only typing answer.. Two thin lenses with focal lengths f1=+150 mm and f2=-100 mm are located d=60 mm apart in air. a) Find, for the lens combination, the effective focal length (feff) and the distances from the lens centres to the principal points (h1 and h2) and the distance between the principle planes (); b) Sketch the system, showing the principal planes and labelling the distances in a). Describe (numerically) the effect of adding the lens 2 to power of the optical system.In the figure below, a diverging lens and concave spherical mirror are positioned along an optical axis, with an object half way between the two. The distance between the lens and mirror is d = 23.6 cm. The magnitude of the mirror's radius of curvature is 20.1 cm, and the lens has a focal length of flens = -19.0 cm. Lens Object Mirror (a) Considering only the light that leaves the object and travels first toward the mirror, locate the final image formed by this system. (Give the magnitude of the image distance in cm, and select its location with respect to the lens.) image distance image location -Select--- (b) Is this image real or virtual? O real O virtual (c) Is it upright or inverted? O upright O inverted (d) What is the overall magnification? cmPlease show all the steps.
- A ray of light is passed through a ruby and it hits a surface in contact with air (n = 1.000) at an angle of 45° with respect to the normal. Use the table below to determine happens when it hits the surface? What is the critical angle? The ray refracts into the air at an angle of 45° with respect to the normal. The ray reflects back into the ruby at an angle of 45° with respect to the normal. The ray refracts at an angle of 90° with respect to the normal, along the surface. The ray is absorbed in the air. None of the above.Please answer the question in the image making sure to answer parts a,b, and c.Draw a principal axis through a convex lens. Label both items clearly. Label 2 focal points located 2.50 cm on each side of the lens. Draw and label a 1.0 cm-tall upright arrow sitting on the principal axis as object 6.00 cm from the lens. Construct two rays from the object, refracting correctly through the center of the lens. Draw and label the image formed.
- Ifa 4.3 cm doll is standing away from a converging lens and the focal length is 8.2 m, find the image distance, magnification, and image height from 4, 8, and 10 m away. Determine if the image is real or virtual, inverted or erect, and smaller or larger. Use the formula below:Case 2: Object distance d0 >R. The figure below shows an arrow-shaped object, located in front of a convex lens at a distance d0 greater than the radius of curvature R. Draw the following rays in the figure: i) Ray parallel to the optical axis; ii) Focal ray; iii) Central ray, iv) Draw the image of the arrow, v) Indicate in the same figure, from where to where di (image-lens distance) is. Use the figure, Do not substitute it with any other figure. Don't forget to put the direction on each ray, both the incident rays and the transmitted rays. Label each ray. Image characteristics for Case 2: Object distance d0 > R. Choose the ones that apply: a) Virtual b) Real c) Inverted d) Increased e) No image is formed f) Equal size g) Reduced h) ErectPlease type the answer instead of hand writting need part B, C and D thanks