How do you calculate T? I don't know how to apply moment in this situation. Opdracht 5.3861X991999p250 m300 mm.с1²250 mm200 mmDE ASU 96DSOF ONG65 N80 mmAD M9.80 NZBLDela2 si0-150 mmT-50 N066y16LBeide wielen zijn bevestigd aan de as zodat een beweging in wiel Adoorgegeven wordt naar wiel B zonder energieverlies. Bereken deBebas de riscuri de pe TK CT GU CD ASU JE ASKMGLSU

Opdracht 5.3 X BE BELEKEL qe absuun gia Reb991 06 300 mm 9P250 mm 200 mm 65 N ASU GE 80 mm A 80 N Z PHP D -150 mm B T 50 N Beide wielen zijn bevestigd aan de as zodat een beweging in wiel A doorgegeven wordt naar wiel B zonder energieverlies. Bereken de

Opdracht 5.3 X BE BELEKEL qe absuun gia Reb991 06 300 mm 9P250 mm 200 mm 65 N ASU GE 80 mm A 80 N Z PHP D -150 mm B T 50 N Beide wielen zijn bevestigd aan de as zodat een beweging in wiel A doorgegeven wordt naar wiel B zonder energieverlies. Bereken de

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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PART 3. VELOCITY ANALYSIS OF ROTATING CRANKS. INSTRUCTIONS: ON A SEPARATE PIECE OF BOND PAPER. SHOW THE COMPLETE SOLUTION AND FINAL ANSWER OF THE FOLLOWING PROBLEMS. 3,600° 1. The instantaneous angular velocity of the crank Q2A is counterclockwise. Q2A = 1.5 in. Find the second instantaneous linear velocity. And draw a graphical interpretation showing the proper length and direction of the velocity arrow of Q2A. Velocity scale: 0.5 in = 10 in/s. Drawing scale: 1:1 2.50 1.50 60° 60°
QUESTION 2 Given the diagram below, determine the following: 2m AD Im kim-1.5m 15m 15 3 kN 3. m- A. Vector form of position vector CB (in m). B. Vector form of position vector DA (in m). 4 kN 2m C. Magnitude of the moment (in kN-m) due to the 3kN force about point D. D. Magnitude of the moment (in kN-m) due to the 4kN force about point C.
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Now consider the figure shown below. N CG -A tip In the above figure the block is just on the verge of tipping: W and N act through point A and thus exert zero torque about point A. The incline angle, Otip, is the incline angle beyond which the block will tip, since increasing the angle beyond Otip will move the CG beyond where there is a point of support below it, as in the previous figure. It is not difficult to show, using some geometry and trigonometry, that Otip is given by Orip = tan' (w / h) (1) Equation (1) agrees with our intuition: If the block is short and wide (h small, w large) the block will be more difficult to tip (Otip is large) and if the block is tall and narrow (h large, w small) the block will be easier to tip (0tip is small). It is now not difficult to see why the automotive industry defines a safety factor describing how easily a vehicle will rollover as (roughly) vehicle width / vehicle height. The larger this safety factor is, the more resistant the vehicle is…
For nos. 21-23, satisfy the conditions of the given problem below: As an airplane's brakes are applied, the nose wheel exerts two forces on the end of the landing gear as shown in the figure 1. Determine: 21. the force in the strut AB. * 1 point 30° 450 lb. 1350 lb O A. 215.3 lb B. 224.4 lb C. 233. 2 lb D. 234.3 lb 1 ft 2 ft
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The secondary unbalanced force is maximum times in one revolution of the crank.
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Consider the Four-Degree-of-Freedom robot shown in figure Q1, and usethe following hints in your answer:Hint 1- Use frames {OO}, {O1} and {O4} as indicated in figure Q1.Hint 2- A joint can undergo a twist and a rotation at the same time
Required Information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A power line pole is subjected to two cable forces of 234 N and 220 N as shown, with each force lying completely in the x-z plane. There is also a supporting guy wire that runs from the ground to the top of the pole and is connected to a small horizontal extension arm at A that extends from the pole. The diameter of the pole is 0.3 m, and the y-axis runs directly along the centerline of the pole. The point where the two cables are attached, point C, is located on the outer perimeter of the pole (i.e., the x-coordinate of point C is 0.15 m) and is in the x-y plane. You want to determine the components of the reactions at the fixed base of the pole, O. The tension in the guy wire that supports the pole is 336 N. Given X1= 234 N X2 = 220 N 0.9 m 40° 50° X1 N X2 N 1.2 m 3 m You decide to first try and solve for the vertical component of the reaction force at O.…
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