Opcode 000 001 010 011 100 101 110 111 Operation O=B O=A^B (bitwise xor) O=A AND B (bitwise and) O=A OR B (bitwise or) O= A + B (addition) O=A - B (subtract) O(7) = 0, 0(6:0) = B (7:1) (logical shift right) O=AB (multiplication) Description Output is equal to input B E Xor of each bit in A with the corresponding bit in B AND of each bit in A with the corresponding bit in B OR of each bit in A with the corresponding bit in B 8 bit addition with a final carry out bit 8 bit subtraction with a borrow out bit Logical shift of the data at input B right by one bit 8 Multiplication. To make our design simpler, we will only keep the lower 8 bits of the result and signal an overflow
Opcode 000 001 010 011 100 101 110 111 Operation O=B O=A^B (bitwise xor) O=A AND B (bitwise and) O=A OR B (bitwise or) O= A + B (addition) O=A - B (subtract) O(7) = 0, 0(6:0) = B (7:1) (logical shift right) O=AB (multiplication) Description Output is equal to input B E Xor of each bit in A with the corresponding bit in B AND of each bit in A with the corresponding bit in B OR of each bit in A with the corresponding bit in B 8 bit addition with a final carry out bit 8 bit subtraction with a borrow out bit Logical shift of the data at input B right by one bit 8 Multiplication. To make our design simpler, we will only keep the lower 8 bits of the result and signal an overflow
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Can you help make a Boolean algebra equation or truth table of the results and simplify it with a k-map for the multiplication part please?
![Opcode
000
001
010
011
100
101
110
111
Operation
O=B
O=AB (bitwise xor)
O=A AND B (bitwise and)
O=A OR B (bitwise or)
O = A + B (addition)
O = A - B (subtract)
O(7) = 0, 0(6:0) = B (7:1)
(logical shift right)
O=AB (multiplication)
Description
Output is equal to input B
-
Xor of each bit in A with the
corresponding bit in B
AND of each bit in A with the
corresponding bit in B
OR of each bit in A with the
corresponding bit in B
8 bit addition with a final carry
out bit
8 bit subtraction with a
borrow out bit
Logical shift of the data at
input B right by one bit
8 Multiplication. To make our
design simpler, we will only
keep the lower 8 bits of the
result and signal an overflow](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F80faba6a-30a4-45ce-b393-fdb8acb57c09%2F59f297d9-b019-4667-9d0d-0bc20c82c18b%2Fbbf2bs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Opcode
000
001
010
011
100
101
110
111
Operation
O=B
O=AB (bitwise xor)
O=A AND B (bitwise and)
O=A OR B (bitwise or)
O = A + B (addition)
O = A - B (subtract)
O(7) = 0, 0(6:0) = B (7:1)
(logical shift right)
O=AB (multiplication)
Description
Output is equal to input B
-
Xor of each bit in A with the
corresponding bit in B
AND of each bit in A with the
corresponding bit in B
OR of each bit in A with the
corresponding bit in B
8 bit addition with a final carry
out bit
8 bit subtraction with a
borrow out bit
Logical shift of the data at
input B right by one bit
8 Multiplication. To make our
design simpler, we will only
keep the lower 8 bits of the
result and signal an overflow
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