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ook for cycles in a graph using the union find data structure? e using uf.connect() on two adjacent points, first check if they're coni e not connected, it means there's a cycle. un uf.connect() on all possible connections. If at least one node is t means there is a cycle

ook for cycles in a graph using the union find data structure? e using uf.connect() on two adjacent points, first check if they're coni e not connected, it means there's a cycle. un uf.connect() on all possible connections. If at least one node is t means there is a cycle

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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How can you look for cycles in a graph using the union find data structure? a. Before using uf.connect() on two adjacent points, first check if they're connected. If they're not connected, it means there's a cycle. O b. You run uf.connect() on all possible connections. If at least one node is not connected, then it means there is a cycle. You run uf.connect() on all possible connections. If at least one node is not connected, Ос. then it means there is no cycle. O d. Before using uf.connect() on two adjacent points, first check if they're connected. If they're connected, it means there's a cycle.
Transcribed Image Text:How can you look for cycles in a graph using the union find data structure? a. Before using uf.connect() on two adjacent points, first check if they're connected. If they're not connected, it means there's a cycle. O b. You run uf.connect() on all possible connections. If at least one node is not connected, then it means there is a cycle. You run uf.connect() on all possible connections. If at least one node is not connected, Ос. then it means there is no cycle. O d. Before using uf.connect() on two adjacent points, first check if they're connected. If they're connected, it means there's a cycle.
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