ook for cycles in a graph using the union find data structure? e using uf.connect() on two adjacent points, first check if they're coni e not connected, it means there's a cycle. un uf.connect() on all possible connections. If at least one node is t means there is a cycle
ook for cycles in a graph using the union find data structure? e using uf.connect() on two adjacent points, first check if they're coni e not connected, it means there's a cycle. un uf.connect() on all possible connections. If at least one node is t means there is a cycle
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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provide an explanation.
![How can you look for cycles in a graph using the union find data structure?
a.
Before using uf.connect() on two adjacent points, first check if they're connected. If
they're not connected, it means there's a cycle.
O b. You run uf.connect() on all possible connections. If at least one node is not connected,
then it means there is a cycle.
You run uf.connect() on all possible connections. If at least one node is not connected,
Ос.
then it means there is no cycle.
O d. Before using uf.connect() on two adjacent points, first check if they're connected. If
they're connected, it means there's a cycle.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F848d742c-7934-4406-9d24-5c5cbf5d57f3%2Fb5a1d76c-a582-46c4-8c34-5b2430f15095%2F86wbib_processed.png&w=3840&q=75)
Transcribed Image Text:How can you look for cycles in a graph using the union find data structure?
a.
Before using uf.connect() on two adjacent points, first check if they're connected. If
they're not connected, it means there's a cycle.
O b. You run uf.connect() on all possible connections. If at least one node is not connected,
then it means there is a cycle.
You run uf.connect() on all possible connections. If at least one node is not connected,
Ос.
then it means there is no cycle.
O d. Before using uf.connect() on two adjacent points, first check if they're connected. If
they're connected, it means there's a cycle.
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