Oo 18. Which expression is a factor of 2x2 + 7x – 15 ? 2x | x + 5 -3 2x + 3

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Algebraic Factorization Practice

**Question 18**

**Which expression is a factor of \(2x^2 + 7x - 15\)?**

- [ ] \(2x - 5\)
- [ ] \(x + 5\)
- [X] \(x - 3\)
- [ ] \(2x + 3\)

To solve this problem, we need to factorize the quadratic expression \(2x^2 + 7x - 15\).

**Step-by-Step Solution:**

1. **Rewrite the middle term \(7x\) using two numbers that multiply to \(2 \cdot (-15) = -30\) and add to \(7\).**
   
   These numbers are \(10\) and \(-3\), since \(10 \times (-3) = -30\) and \(10 + (-3) = 7\).

2. **Split the middle term \(7x\) accordingly:**
   \[
   2x^2 + 10x - 3x - 15
   \]

3. **Group the terms:**
   \[
   (2x^2 + 10x) - (3x + 15)
   \]

4. **Factor out the common terms from each group:**
   \[
   2x(x + 5) - 3(x + 5)
   \]

5. **Factor out the common binomial \((x + 5)\):**
   \[
   (2x - 3)(x + 5)
   \]

As a result, the expression is factored into \((2x - 3)(x + 5)\). Therefore, the factor \((x - 3)\) is **not** a correct factor. This may indicate that an error was made during factoring; let us recheck the process. 

The factorization seems accurate if revisited, and our answer could have been a check-mark error.

### Correct Factorization:

Given the conflicting previous steps and correct answer:

- Correctly determining one's factor error is essential for correct algebraic practices.

**Note:** Proper quadratic factorization enhances solving efficiency and verification skills.

For further problems and detailed algebraic concept discussions, please visit our provided educational sections.
Transcribed Image Text:### Algebraic Factorization Practice **Question 18** **Which expression is a factor of \(2x^2 + 7x - 15\)?** - [ ] \(2x - 5\) - [ ] \(x + 5\) - [X] \(x - 3\) - [ ] \(2x + 3\) To solve this problem, we need to factorize the quadratic expression \(2x^2 + 7x - 15\). **Step-by-Step Solution:** 1. **Rewrite the middle term \(7x\) using two numbers that multiply to \(2 \cdot (-15) = -30\) and add to \(7\).** These numbers are \(10\) and \(-3\), since \(10 \times (-3) = -30\) and \(10 + (-3) = 7\). 2. **Split the middle term \(7x\) accordingly:** \[ 2x^2 + 10x - 3x - 15 \] 3. **Group the terms:** \[ (2x^2 + 10x) - (3x + 15) \] 4. **Factor out the common terms from each group:** \[ 2x(x + 5) - 3(x + 5) \] 5. **Factor out the common binomial \((x + 5)\):** \[ (2x - 3)(x + 5) \] As a result, the expression is factored into \((2x - 3)(x + 5)\). Therefore, the factor \((x - 3)\) is **not** a correct factor. This may indicate that an error was made during factoring; let us recheck the process. The factorization seems accurate if revisited, and our answer could have been a check-mark error. ### Correct Factorization: Given the conflicting previous steps and correct answer: - Correctly determining one's factor error is essential for correct algebraic practices. **Note:** Proper quadratic factorization enhances solving efficiency and verification skills. For further problems and detailed algebraic concept discussions, please visit our provided educational sections.
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