onsider these reactions, where M represents a generic metal. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)Δ?1=−938.0 kJ2M(s)+6HCl(aq)⟶2⁢MCl3⁢(aq)+3⁢H2⁡(g)⁢Δ⁢H1=−938.0 kJ HCl(g)⟶HCl(aq)  Δ?2=−74.8 kJHCl(g)⟶HCl(aq)  Δ⁢H2=−74.8 kJ H2(g)+Cl2(g)⟶2HCl(g) Δ?3=−1845.0 kJH2⁡(g)+Cl2⁢(g)⟶2HCl(g) Δ⁢H3=−1845.0 kJ MCl3(s)⟶MCl3(aq)  Δ?4=−160.0 kJMCl3⁢(s)⟶MCl3⁢(aq)

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Chapter1: Chemical Foundations
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Consider these reactions, where M represents a generic metal.

  1. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)Δ?1=−938.0 kJ2M(s)+6HCl(aq)⟶2⁢MCl3⁢(aq)+3⁢H2⁡(g)⁢Δ⁢H1=−938.0 kJ
  2. HCl(g)⟶HCl(aq)  Δ?2=−74.8 kJHCl(g)⟶HCl(aq)  Δ⁢H2=−74.8 kJ
  3. H2(g)+Cl2(g)⟶2HCl(g) Δ?3=−1845.0 kJH2⁡(g)+Cl2⁢(g)⟶2HCl(g) Δ⁢H3=−1845.0 kJ
  4. MCl3(s)⟶MCl3(aq)  Δ?4=−160.0 kJMCl3⁢(s)⟶MCl3⁢(aq)  Δ⁢H4=−160.0 kJ

Use the given information to determine the enthalpy of the reaction

 

2M(s)+3Cl2(g)⟶2MCl3(s)

 

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