onsider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS=42000 km. Consider the mechanical energy of the same body on Earth at the South pole, at re=6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.) G=6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97
onsider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS=42000 km. Consider the mechanical energy of the same body on Earth at the South pole, at re=6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.) G=6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97
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Chapter1: Units, Trigonometry. And Vectors
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Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS=42000 km.
Consider the mechanical energy of the same body on Earth at the South pole, at re=6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.)
G=6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97×1024 kg
What is the difference in the mechanical energy per kilogram between the two?
E =E= ___ MJ.kg−1 (to two significant figures, don't use scientific notation)
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