onsider the equilibrium system described by ne chemical reaction below. For this reaction, p = 109 at 298 K. If the equilibrium partial ressures of Br, and NOBr at 0.0159 atm and .0768 atm, respectively, determine the partial ressure of NO at equilibrium... 2 NO(g) + Br2(g) =2 NOBr(g) 1 2 Based on your expression for Kp, solve for the equilibrium partial pressure of NO. PNO = atm 5 RESET 0.0443 6.36 526 1.70 x 10-3 0.0583
onsider the equilibrium system described by ne chemical reaction below. For this reaction, p = 109 at 298 K. If the equilibrium partial ressures of Br, and NOBr at 0.0159 atm and .0768 atm, respectively, determine the partial ressure of NO at equilibrium... 2 NO(g) + Br2(g) =2 NOBr(g) 1 2 Based on your expression for Kp, solve for the equilibrium partial pressure of NO. PNO = atm 5 RESET 0.0443 6.36 526 1.70 x 10-3 0.0583
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Question 1 of 25
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Consider the equilibrium system described by
the chemical reaction below. For this reaction,
Kp = 109 at 298 K. If the equilibrium partial
pressures of Br, and NOBr at 0.0159 atm and
0.0768 atm, respectively, determine the partial
pressure of NO at equilibrium..
2 NO(g) + Br2(g) = 2 NOBr(g)
1
2
Based on your expression for Kp, solve for the
equilibrium partial pressure of NO.
PNO =
atm
RESET
0.0443
6.36
526
1.70 x 10-3
0.0583
Tap here or pull up for additional resources"
Transcribed Image Text:8:37
ull ?
Question 1 of 25
Submit
Consider the equilibrium system described by
the chemical reaction below. For this reaction,
Kp = 109 at 298 K. If the equilibrium partial
pressures of Br, and NOBr at 0.0159 atm and
0.0768 atm, respectively, determine the partial
pressure of NO at equilibrium..
2 NO(g) + Br2(g) = 2 NOBr(g)
1
2
Based on your expression for Kp, solve for the
equilibrium partial pressure of NO.
PNO =
atm
RESET
0.0443
6.36
526
1.70 x 10-3
0.0583
Tap here or pull up for additional resources

Transcribed Image Text:8:37
ull ?
Question 1 of 25
Submit
Consider the equilibrium system described by
the chemical reaction below. For this reaction,
Kp = 109 at 298 K. If the equilibrium partial
pressures of Br, and NOBr at 0.0159 atm and
0.0768 atm, respectively, determine the partial
pressure of NO at equilibrium..
2 NO(g) + Br2(g) =2 NOB1(g)
1
2
If (x) represents the equilibrium partial pressure
of NO, set up the equilibrium expression for Kp
to solve for the partial pressure. Do not combine
or simplify terms..
Kp
= 109
RESET
(109)
(0.0159)
(0.0768)
2(0.0159)
2(0.0768)
(0.0159)²
(0.0768)?
(x)
(2x)
(x)2
(2x)2
Tap here or pull up for additional resources
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