Only answer H, I, and J. I already have answers from A to G.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Only answer H, I, and J. I already have answers from A to G.
Transcribed Image Text:The numbers of branches of the 50 top libraries are shown.
67
84
80
77
97
59
62
37
33
42
36
54
18
12
19
33
49
24
25
22
24
29
9
21
21
24
31
17
15
21
13
19
19
22
22
30
41
22
18
20
26
33
14
14
16
22
26
10
16
24
Source: The World Almanac and Book of Facts.
a. Construct a frequency distribution for the data.
Frequency distribution table:
Class
Frequency
9- 24
28
25 - 40
11
41 - 56
4
57 - 72
3
73 - 88
3
89 - 104
Total
50
b. Construct a histogram for the data.
30- 28
25
20
15
11
10-
5
3
1
9
25
41
57 73
89
105
Histogram (Frequency Diagram)
c. Describe the shape of the histogram.
Shape of the distribution is right skewed.
d. Based on your answer to question 3, do you feel that the distribution is approximately
normal?
The distribution is not bell shaped. Hence it is not approximately normal.
Kouanba
Transcribed Image Text:In addition to the histogram, distributions that are approximately normal have about 68%
of the values fall within 1 standard deviation of the mean, about 95% of the data values fall within
2 standard deviations of the mean, and almost 100% of the data values fall within
3 standard deviations of the mean.
e. Find the mean and standard deviation for the data.
I=A + hū
=48. 5 + 16 x
Σ
–55
=48. 5 + 16 x
50
=30.9
Mean is 30.9
o²=h? x
Σ
=16° x [ - ()
=256 x (2.94 – 1.21)
=256 x 1. 73
=442. 88
a=V442. 88
=21.04
Standard deviation is 21.4
f. What percent of the data values fall within 1 standard deviation of the mean?
CI=T± lo
=30.9 + 21.04
=(30.9 – 21.04, 30. 9 + 21. 04)
=(9. 86, 51.94)
Thus, the percentage of data lie within one standard deviation is 9.86 and 51.94
g. What percent of the data values fall within 2 standard deviations of the mean?
Cl=i± 20
=30.9 + 2 x 21.04
=(30.9 – 42.08, 30.9 + 42. 08)
=(-11. 18, 72.98)
Thus, the percentage of data lie within two standard deviation is -11.18 and 72.98
h. What percent of the data values fall within 3 standard deviations of the mean?
i. How do your answers to questions 6, 7, and 8 compare to 68, 95, and 100%, respectively?
j. Does your answer help support the conclusion you reached in question 4? Explain.
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