One way to produce a beam of polarized light with intensity I and polarization angle would be to pass unpolarized light with intensity Is through a polarizer whose transmission axis is oriented such that @TA = 0. How large must I be if the transmitted light is to have intensity I? (Figure 3) Express your answer as a decimal number times the symbol I. For example, if I = (1/4)I. enter 0.25 * I.

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Learning Goal:
To understand polarization of light and how to use Malus's law to calculate the intensity of a
beam of light after passing through one or more polarizing filters.
The two transverse waves shown in the figure(Figure 1) both travel in the +z direction. The
waves differ in that the top wave oscillates horizontally and the bottom wave oscillates
vertically. The direction of oscillation of a wave is called the polarization of the wave. The
upper wave is described as polarized in the +x direction whereas the lower wave is
polarized in the +y direction. In general, waves can be polarized along any direction.
Recall that electromagnetic waves, such as visible light, microwaves, and X rays, consist of
oscillating electric and magnetic fields. The polarization of an electromagnetic wave refers
to the oscillation direction of the electric field, not the magnetic field. In this problem all
figures depicting light waves illustrate only the electric field.
A linear polarizing filter, often just called a polarizer, is a device that only transmits light
polarized along a specific transmission axis direction. The amount of light that passes
through a filter is quantified in terms of its intensity. If the polarization angle of the incident
light matches the transmission axis of the polarizer, 100% of the light will pass through, so
the transmitted intensity will equal the incident intensity. More generally, the intensity of light
emerging from a polarizer is described by Malus's law:
I= Io cos² 0.
where I, is the intensity of the polarized light beam just before entering the polarizer, I is
the intensity of the transmitted light beam immediately after passing through the polarizer,
and is the angular difference between the polarization angle of the incident beam and the
transmission axis of the polarizer. After passing through the polarizer, the transmitted light is
polarized in the direction of the transmission axis of the polarizing filter.
Figure
Incident
natural
light
Polarizer
3 of 3
Transcribed Image Text:Learning Goal: To understand polarization of light and how to use Malus's law to calculate the intensity of a beam of light after passing through one or more polarizing filters. The two transverse waves shown in the figure(Figure 1) both travel in the +z direction. The waves differ in that the top wave oscillates horizontally and the bottom wave oscillates vertically. The direction of oscillation of a wave is called the polarization of the wave. The upper wave is described as polarized in the +x direction whereas the lower wave is polarized in the +y direction. In general, waves can be polarized along any direction. Recall that electromagnetic waves, such as visible light, microwaves, and X rays, consist of oscillating electric and magnetic fields. The polarization of an electromagnetic wave refers to the oscillation direction of the electric field, not the magnetic field. In this problem all figures depicting light waves illustrate only the electric field. A linear polarizing filter, often just called a polarizer, is a device that only transmits light polarized along a specific transmission axis direction. The amount of light that passes through a filter is quantified in terms of its intensity. If the polarization angle of the incident light matches the transmission axis of the polarizer, 100% of the light will pass through, so the transmitted intensity will equal the incident intensity. More generally, the intensity of light emerging from a polarizer is described by Malus's law: I= Io cos² 0. where I, is the intensity of the polarized light beam just before entering the polarizer, I is the intensity of the transmitted light beam immediately after passing through the polarizer, and is the angular difference between the polarization angle of the incident beam and the transmission axis of the polarizer. After passing through the polarizer, the transmitted light is polarized in the direction of the transmission axis of the polarizing filter. Figure Incident natural light Polarizer 3 of 3
Part D
One way to produce a beam of polarized light with intensity I and polarization angle would be to pass unpolarized light with intensity Io through a polarizer whose transmission axis is oriented such that 0TA = 0.
How large must Io be if the transmitted light is to have intensity I? (Figure 3)
Express your answer as a decimal number times the symbol I. For example, if Io = (1/4)I. enter 0.25 * 1.
ΑΣΦ
Io =
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Transcribed Image Text:Part D One way to produce a beam of polarized light with intensity I and polarization angle would be to pass unpolarized light with intensity Io through a polarizer whose transmission axis is oriented such that 0TA = 0. How large must Io be if the transmitted light is to have intensity I? (Figure 3) Express your answer as a decimal number times the symbol I. For example, if Io = (1/4)I. enter 0.25 * 1. ΑΣΦ Io = Submit Previous Answers Request Answer
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