One UOW student monitored 12 mm of rainfall in one-hour duration, he noticed the initial loss of rainfall from a car park is 1 mm. How much runoff was generated from the 2km² campus in this storm, if the continuous loss is 1mm/hour? m³ V=
One UOW student monitored 12 mm of rainfall in one-hour duration, he noticed the initial loss of rainfall from a car park is 1 mm. How much runoff was generated from the 2km² campus in this storm, if the continuous loss is 1mm/hour? m³ V=
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![**Rainfall Runoff Calculation**
One UOW student monitored 12 mm of rainfall in one-hour duration. He noticed the initial loss of rainfall from a car park is 1 mm. How much runoff was generated from the 2 km² campus in this storm, if the continuous loss is 1 mm/hour?
\[ V = \_\_\_\_\_\_ \, \text{m}^3 \]
**Explanation:**
To calculate the runoff generated from the campus, consider the following:
1. **Rainfall amount**: 12 mm
2. **Initial loss**: 1 mm
3. **Continuous loss**: 1 mm/hour
The total effective rainfall that contributes to runoff can be calculated by subtracting the losses from the total rainfall.
Firstly, the effective rainfall is:
\[ 12 \, \text{mm} - 1 \, \text{mm} (\text{initial loss}) = 11 \, \text{mm} \]
However, because the continuous loss is 1 mm/hour, we subtract that from the effective rainfall for the one-hour period:
\[ 11 \, \text{mm} - 1 \, \text{mm} (\text{continuous loss}) = 10 \, \text{mm} \]
To find the volume of runoff, we convert the effective rainfall to meters and multiply by the area of the campus:
\- Convert 10 mm to meters:
\[ 10 \, \text{mm} = 0.01 \, \text{m} \]
\- Area of the campus:
\[ 2 \, \text{km}^2 = 2 \times 10^6 \, \text{m}^2 \]
Runoff volume:
\[ V = \text{effective rainfall} \times \text{area} \]
\[ V = 0.01 \, \text{m} \times 2 \times 10^6 \, \text{m}^2 \]
\[ V = 20,000 \, \text{m}^3 \]
Therefore, the runoff generated from the 2 km² campus is:
\[ V = 20,000 \, \text{m}^3 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F03256047-c4d6-4acb-b3bb-18185f2c131a%2F23ba861b-7981-4f7c-9871-be38b3ff9c51%2Fs8pyzvb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Rainfall Runoff Calculation**
One UOW student monitored 12 mm of rainfall in one-hour duration. He noticed the initial loss of rainfall from a car park is 1 mm. How much runoff was generated from the 2 km² campus in this storm, if the continuous loss is 1 mm/hour?
\[ V = \_\_\_\_\_\_ \, \text{m}^3 \]
**Explanation:**
To calculate the runoff generated from the campus, consider the following:
1. **Rainfall amount**: 12 mm
2. **Initial loss**: 1 mm
3. **Continuous loss**: 1 mm/hour
The total effective rainfall that contributes to runoff can be calculated by subtracting the losses from the total rainfall.
Firstly, the effective rainfall is:
\[ 12 \, \text{mm} - 1 \, \text{mm} (\text{initial loss}) = 11 \, \text{mm} \]
However, because the continuous loss is 1 mm/hour, we subtract that from the effective rainfall for the one-hour period:
\[ 11 \, \text{mm} - 1 \, \text{mm} (\text{continuous loss}) = 10 \, \text{mm} \]
To find the volume of runoff, we convert the effective rainfall to meters and multiply by the area of the campus:
\- Convert 10 mm to meters:
\[ 10 \, \text{mm} = 0.01 \, \text{m} \]
\- Area of the campus:
\[ 2 \, \text{km}^2 = 2 \times 10^6 \, \text{m}^2 \]
Runoff volume:
\[ V = \text{effective rainfall} \times \text{area} \]
\[ V = 0.01 \, \text{m} \times 2 \times 10^6 \, \text{m}^2 \]
\[ V = 20,000 \, \text{m}^3 \]
Therefore, the runoff generated from the 2 km² campus is:
\[ V = 20,000 \, \text{m}^3 \]
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