One UOW student monitored 12 mm of rainfall in one-hour duration, he noticed the initial loss of rainfall from a car park is 1 mm. How much runoff was generated from the 2km² campus in this storm, if the continuous loss is 1mm/hour? m³ V=

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**Rainfall Runoff Calculation**

One UOW student monitored 12 mm of rainfall in one-hour duration. He noticed the initial loss of rainfall from a car park is 1 mm. How much runoff was generated from the 2 km² campus in this storm, if the continuous loss is 1 mm/hour?

\[ V = \_\_\_\_\_\_ \, \text{m}^3 \]

**Explanation:**

To calculate the runoff generated from the campus, consider the following:

1. **Rainfall amount**: 12 mm
2. **Initial loss**: 1 mm
3. **Continuous loss**: 1 mm/hour

The total effective rainfall that contributes to runoff can be calculated by subtracting the losses from the total rainfall.

Firstly, the effective rainfall is:
\[ 12 \, \text{mm} - 1 \, \text{mm} (\text{initial loss}) = 11 \, \text{mm} \]

However, because the continuous loss is 1 mm/hour, we subtract that from the effective rainfall for the one-hour period:
\[ 11 \, \text{mm} - 1 \, \text{mm} (\text{continuous loss}) = 10 \, \text{mm} \]

To find the volume of runoff, we convert the effective rainfall to meters and multiply by the area of the campus:

\- Convert 10 mm to meters:
\[ 10 \, \text{mm} = 0.01 \, \text{m} \]

\- Area of the campus:
\[ 2 \, \text{km}^2 = 2 \times 10^6 \, \text{m}^2 \]

Runoff volume:
\[ V = \text{effective rainfall} \times \text{area} \]
\[ V = 0.01 \, \text{m} \times 2 \times 10^6 \, \text{m}^2 \]
\[ V = 20,000 \, \text{m}^3 \]

Therefore, the runoff generated from the 2 km² campus is:
\[ V = 20,000 \, \text{m}^3 \]
Transcribed Image Text:**Rainfall Runoff Calculation** One UOW student monitored 12 mm of rainfall in one-hour duration. He noticed the initial loss of rainfall from a car park is 1 mm. How much runoff was generated from the 2 km² campus in this storm, if the continuous loss is 1 mm/hour? \[ V = \_\_\_\_\_\_ \, \text{m}^3 \] **Explanation:** To calculate the runoff generated from the campus, consider the following: 1. **Rainfall amount**: 12 mm 2. **Initial loss**: 1 mm 3. **Continuous loss**: 1 mm/hour The total effective rainfall that contributes to runoff can be calculated by subtracting the losses from the total rainfall. Firstly, the effective rainfall is: \[ 12 \, \text{mm} - 1 \, \text{mm} (\text{initial loss}) = 11 \, \text{mm} \] However, because the continuous loss is 1 mm/hour, we subtract that from the effective rainfall for the one-hour period: \[ 11 \, \text{mm} - 1 \, \text{mm} (\text{continuous loss}) = 10 \, \text{mm} \] To find the volume of runoff, we convert the effective rainfall to meters and multiply by the area of the campus: \- Convert 10 mm to meters: \[ 10 \, \text{mm} = 0.01 \, \text{m} \] \- Area of the campus: \[ 2 \, \text{km}^2 = 2 \times 10^6 \, \text{m}^2 \] Runoff volume: \[ V = \text{effective rainfall} \times \text{area} \] \[ V = 0.01 \, \text{m} \times 2 \times 10^6 \, \text{m}^2 \] \[ V = 20,000 \, \text{m}^3 \] Therefore, the runoff generated from the 2 km² campus is: \[ V = 20,000 \, \text{m}^3 \]
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