One study claimed that 86%86% of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 134134 college students and finds that 109109 of them identify themselves as procrastinators. Does this evidence support the professor’s claim that fewer than 86%86% of college students are procrastinators? Use a 0.050.05 level of significance.   Step 2 of 3 :   Compute the value of the test statistic.

Q: A random sample of 860 births in New york state included 434 girls. Use a 0.05 significance level to…

A: The aim is to test the claim that 48.8% of newborn babies are girls. The test hypotheses are given…

Q: The U.S. Energy Information Administration claimed that U.S. residential customers used an average…

A: In hypothesis testing, we start by stating the null hypothesis (H0) and the alternative hypothesis…

Q: The U.S. Energy Information Administration claimed that U.S. residential customers used an average…

A: In hypothesis testing, we start by stating the null hypothesis (H0) and the alternative hypothesis…

Q: n​ 2010, shortly before a​ country's midterm​ elections, people in that country were dissatisfied…

A: Given: 59​% of adults in the country thought that a third major party was needed; p=0.59 62​% of…

Q: 10 years ago, a Gallop Poll reported that 79% of people reported that they enjoy driving their car.…

A: Given: Population proportionp=0.79Number of trials(n)=1048Number of successes (x)=734

Q: One study claimed that 87%87% of college students identify themselves as procrastinators. A…

A: Given:Sample size (n) = 174143 of them identify themselves as procrastinators. The claim is that…

Q: identify themselves as procrastinators. A professor believes that the claim regarding college…

A: Given P=0.87 X=133 n=161

Q: suppose 223 subjects are treated with a drug that is used to treat pain and 52 of them developed…

A: Null Hypothesis: A hypothesis which is tested for plausible rejection is called the Null Hypothesis…

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A: (a). Compute the sample test statistic: Null and alternate hypotheses: The investigator is…

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A: We have given that  Sample size n1= 44 , n2= 52 Sample mean xbar1 = 4.9 , xbar2 = 5.7 Known standard…

Q: A survey of 1200 TV households showed that 53.5% of them had at least one stand-alone streaming…

A: Let p be the population proportion  p=majority=1/2=0.50=50%, n=1200, p^=sample…

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A:

Q: Round your all answers to two decimal places. a. What is the point estimate of the difference…

A:

Q: In a random sample of soldiers who fought in the Battle of Preston, 774 soldiers were from the New…

A: The hypotheses are given below: Null hypothesis: H0:p=0.25 Alternative hypothesis: H1:p>0.25 The…

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A: The level of significance is 0.05.

Q: Researchers wish to test whether marijuana use among full-time college students aged 19-22 at a…

A: 1) The appropriate Null and Alternative Hypotheses are given below: From the given information, the…

Q: One study claimed that 92%92% of college students identify themselves as procrastinators. A…

A: Given p=0.92, n=278 and x=247

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A: Given: n1 = 47 X1 = 4.9 σ1 = 1.2 n2 = 43 X2 = 5.5 σ2 = 1.4 α = 0.05 Formula Used: Test-statistic Z =…

Q: n a survey of 1000 women age 22 to 35 who work full time, 555 indicated that they would be willing…

A: Given,   The sample proportion is,

Q: Answer 囲 Tables Keypad Keyboard Shortcuts We reject the null hypothesis and conclude that there is…

A: Given : sample size, n = 189 sample mean, x̄ = 10628 population standard…

Q: The U.S. Energy Information Administration claimed that U.S. residential customers used an average…

A: The given values are:Population mean (μ) = 10,476 kWhSample mean (x̄) = 10,767 kWhPopulation…

Q: Suppose 243 subjects are treated with a drug that is used to treat pain and 50 of them developed…

A: Given, The number of subjects treated with a drug that is used to treat pain is n=243 The number of…

Q: Sketch the sampling distribution and show the area corresponding to the P-value. b a -2 -1 O-3 -2 -1…

A:

Q: It is believed that 11% of all Americans are left-handed. A college needs to know how many…

A: Given that  Sample size n =200 Favorable cases x =30 Sample proportion p^=x/n  =30/200 =0.15

Q: USA Today (Feb. 17, 2011) described a survey of 1,008 American adults. One question on the survey…

A: a) The sample proportion is p-cap = 205/1008           = 0.203 b) The population proportion p is…

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A: a) The level of significance is 0.05.

Q: The Mayoral challenger claims that less than 30% of residents over the age of 25 have bachelor's…

A:

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A: Given information- Significance level, α = 0.05 We have given two samples- For sample 1- Sample…

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A:

Q: TV subscription streaming. “Streaming" of television pro- grams is trending upward. According to The…

A: Denote p as the true fraction of adult TV viewers who are subscription streams.

Q: A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point…

A: Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If…

Q: The National Academy of Science reported that 41% of research in mathematics is published by US…

A: Given,n=186x=92p^=xnp^=92186=0.4946α=0.05

Q: Suppose that in a random selection of 100100 colored​ candies, 2323​% of them are blue. The candy…

A: Let p is population proportion of blue candies.Given information:Sample size (n) = 100Significance…

Q: company claims that at least 94% of equipment supplied to a manufacturer is within specifications. A…

A:

Q: identify themselves as procrastinators. Does this evidence support the professor’s claim that fewer…

A: n=118,X=102,p=91%=0.91α=0.01