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The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are distributed normally. Justification:

The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are distributed normally. Justification:

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Could you please help me with how to graph this on a TI-84 plus CE as I have put in the correct numbers but when I hit graph, I cannot see the graph at all. What settings would I need to change under the windows option to be able to see this type of graph? Thank you.

Given info: The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are distributed normally. Justification: The normal curve is, 180 220 260 300 μ=300 340 380 μ-o = 263 300- o = 263 -0 = 263-300 o = 37 Thus, the standard deviation of the normal curve is 37. 420 From the normal curve, it can be observed that the normal curve is symmetric at the point 300. That is, the mean of the normal curve is 300 and the inflection points are one standard deviation from the mean are 263 and 337. One standard deviation from the mean is, μ+ o = 337 and μ-o = 263 Substitute 300 for μ then μ+ 0 = 337 300+ 0 = 337 o = 337-300 = 37
Transcribed Image Text:Given info: The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are distributed normally. Justification: The normal curve is, 180 220 260 300 μ=300 340 380 μ-o = 263 300- o = 263 -0 = 263-300 o = 37 Thus, the standard deviation of the normal curve is 37. 420 From the normal curve, it can be observed that the normal curve is symmetric at the point 300. That is, the mean of the normal curve is 300 and the inflection points are one standard deviation from the mean are 263 and 337. One standard deviation from the mean is, μ+ o = 337 and μ-o = 263 Substitute 300 for μ then μ+ 0 = 337 300+ 0 = 337 o = 337-300 = 37
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One question, my graph keeps going with an area of = 1 even though I typed in .5  Is there another setting I need to change for my graph to match yours?

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