The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are distributed normally. Justification:
The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are distributed normally. Justification:
A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Good morning,
Could you please help me with how to graph this on a TI-84 plus CE as I have put in the correct numbers but when I hit graph, I cannot see the graph at all. What settings would I need to change under the windows option to be able to see this type of graph? Thank you.
![Given info:
The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are
distributed normally.
Justification:
The normal curve is,
180
220
260
300
μ=300
340
380
μ-o = 263
300- o = 263
-0 = 263-300
o = 37
Thus, the standard deviation of the normal curve is 37.
420
From the normal curve, it can be observed that the normal curve is symmetric at the point 300. That is, the
mean of the normal curve is 300 and the inflection points are one standard deviation from the mean are 263
and 337.
One standard deviation from the mean is,
μ+ o = 337 and μ-o = 263
Substitute 300 for μ then
μ+ 0 = 337
300+ 0 = 337
o = 337-300
= 37](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa5b9ab80-c15e-46d7-8003-c733ab4df490%2F6ecd647d-7277-4d24-ac63-982fc14008ce%2Fay9r19_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given info:
The scaled test scores for the New York State Grade 4 Common Core English Language Arts Test are
distributed normally.
Justification:
The normal curve is,
180
220
260
300
μ=300
340
380
μ-o = 263
300- o = 263
-0 = 263-300
o = 37
Thus, the standard deviation of the normal curve is 37.
420
From the normal curve, it can be observed that the normal curve is symmetric at the point 300. That is, the
mean of the normal curve is 300 and the inflection points are one standard deviation from the mean are 263
and 337.
One standard deviation from the mean is,
μ+ o = 337 and μ-o = 263
Substitute 300 for μ then
μ+ 0 = 337
300+ 0 = 337
o = 337-300
= 37
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One question, my graph keeps going with an area of = 1 even though I typed in .5 Is there another setting I need to change for my graph to match yours?
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