One of your students solves the following equation and can't figure out why she only got two solutions rather than three like everyone else. She lost the solution x = 3. How do you explain to her what happened? x(x − 3) = x(x − 3)(x − 1) x(x − 3) _ x(x − 3)(x − 1) x - 3 x - 3 = x = x(x - 1) x = x² - X x² 2x = 0 x(x − 2) = 0 x = 0, x = 2
One of your students solves the following equation and can't figure out why she only got two solutions rather than three like everyone else. She lost the solution x = 3. How do you explain to her what happened? x(x − 3) = x(x − 3)(x − 1) x(x − 3) _ x(x − 3)(x − 1) x - 3 x - 3 = x = x(x - 1) x = x² - X x² 2x = 0 x(x − 2) = 0 x = 0, x = 2
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:One of your students solves the following equation and can't figure out why she only got two
solutions rather than three like everyone else. She lost the solution x = 3. How do you explain to
her what happened?
x(x − 3) = x(x − 3)(x − 1)
x(x − 3) _ x(x − 3)(x − 1)
x - 3
x - 3
=
x = x(x - 1)
x = x² - X
x²
2x = 0
x(x − 2) = 0
x = 0, x = 2
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