One end of the horizontal rope is attached to a prong of an electrically driven tuning fork that vibrates a rope transversely at 250HZ. The other end passes over a pulley and supports at 3 kg mass. The liner mass density of the rope is 0.048 kg/m. What is the speed of a transverse waves on the rope? (m/s)

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

One end of the horizontal rope is attached to a prong of an electrically driven tuning fork that vibrates a rope transversely at 250 Hz. The other end passes over a pulley and supports a 3 kg mass. The linear mass density of the rope is 0.048 kg/m.

**Question:**

What is the speed of transverse waves on the rope? (m/s)

**Solution:**

To determine the speed of transverse waves on the rope, we can use the following formula for wave speed on a rope under tension:

\[ v = \sqrt{\frac{T}{\mu}} \]

where:
- \( v \) is the wave speed,
- \( T \) is the tension in the rope,
- \( \mu \) is the linear mass density of the rope.

**Step-by-step Calculation:**

1. **Calculate the tension in the rope (T):**
   
   Tension (T) is created by the weight of the mass hanging at the end of the rope.
   \[ T = mg \]
   where:
   - \( m \) is the mass (3 kg),
   - \( g \) is the acceleration due to gravity (approximated as 9.8 m/s²).

   Substitute the values:
   \[ T = 3 \, \text{kg} \times 9.8 \, \text{m/s}^2 \]
   \[ T = 29.4 \, \text{N} \]

2. **Calculate the wave speed (v):**
   
   Use the formula for the wave speed:
   \[ v = \sqrt{\frac{T}{\mu}} \]
   where:
   - \( \mu \) is given as 0.048 kg/m.

   Substitute the values:
   \[ v = \sqrt{\frac{29.4 \, \text{N}}{0.048 \, \text{kg/m}}} \]
   \[ v = \sqrt{612.5 \, \text{m}^2/\text{s}^2} \]
   \[ v \approx 24.74 \, \text{m/s} \]

**Answer:**

The speed of transverse waves on the rope is approximately 24.74 m/s.
Transcribed Image Text:**Problem Statement:** One end of the horizontal rope is attached to a prong of an electrically driven tuning fork that vibrates a rope transversely at 250 Hz. The other end passes over a pulley and supports a 3 kg mass. The linear mass density of the rope is 0.048 kg/m. **Question:** What is the speed of transverse waves on the rope? (m/s) **Solution:** To determine the speed of transverse waves on the rope, we can use the following formula for wave speed on a rope under tension: \[ v = \sqrt{\frac{T}{\mu}} \] where: - \( v \) is the wave speed, - \( T \) is the tension in the rope, - \( \mu \) is the linear mass density of the rope. **Step-by-step Calculation:** 1. **Calculate the tension in the rope (T):** Tension (T) is created by the weight of the mass hanging at the end of the rope. \[ T = mg \] where: - \( m \) is the mass (3 kg), - \( g \) is the acceleration due to gravity (approximated as 9.8 m/s²). Substitute the values: \[ T = 3 \, \text{kg} \times 9.8 \, \text{m/s}^2 \] \[ T = 29.4 \, \text{N} \] 2. **Calculate the wave speed (v):** Use the formula for the wave speed: \[ v = \sqrt{\frac{T}{\mu}} \] where: - \( \mu \) is given as 0.048 kg/m. Substitute the values: \[ v = \sqrt{\frac{29.4 \, \text{N}}{0.048 \, \text{kg/m}}} \] \[ v = \sqrt{612.5 \, \text{m}^2/\text{s}^2} \] \[ v \approx 24.74 \, \text{m/s} \] **Answer:** The speed of transverse waves on the rope is approximately 24.74 m/s.
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