One edge of a painting is 6 in. longer than the shorter edge. The picture has a 2-in.-wide frame. There is one rectangle inside the other rectangle. The distance between two edges of two rectangles is 2. The length of the rectangle is x + 6 and width is x. The portion between two rectangles is shaded. Part A Which quadratic function represents the total area of the picture and frame? A. f(x) = x2 + 8x + 12 B. f(x) = x2 + 10x + 24 C. f(x) = x2 + 12x + 32 D. f(x) = x2 + 14x + 40 Part B What is the total area of the %3D %3D framed picture if its shorter edge is 8 inches long? Enter your answer in the box. _in.2 x+ 6

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
One edge of a painting is 6 in.
longer than the shorter edge.
The picture has a 2-in.-wide
frame. There is one rectangle
inside the other rectangle. The
distance between two edges of
two rectangles is 2. The length
of the rectangle is x + 6 and
width is x. The portion between
two rectangles is shaded.
Part A
Which quadratic function
represents the total area of the
picture and frame?
A. f(x) = x2 + 8x + 12
B. f(x) = x2 + 10x + 24
C. f(x) = x2 + 12x + 32
D. f(x) = x2 + 14x + 40
Part B
What is the total area of the
%3D
%3D
%3D
framed picture if its shorter
edge is 8 inches long?
Enter your answer in the box.
_in.2
X+ 6
Transcribed Image Text:One edge of a painting is 6 in. longer than the shorter edge. The picture has a 2-in.-wide frame. There is one rectangle inside the other rectangle. The distance between two edges of two rectangles is 2. The length of the rectangle is x + 6 and width is x. The portion between two rectangles is shaded. Part A Which quadratic function represents the total area of the picture and frame? A. f(x) = x2 + 8x + 12 B. f(x) = x2 + 10x + 24 C. f(x) = x2 + 12x + 32 D. f(x) = x2 + 14x + 40 Part B What is the total area of the %3D %3D %3D framed picture if its shorter edge is 8 inches long? Enter your answer in the box. _in.2 X+ 6
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