One component of a magnetic field has a magnitude of 0.0450 T and points along the +x axis, while the other component has a magnitude of 0.0702 T and points along the -y axis. A particle carrying a charge of +2.23 × 10-5 C is moving along the +z axis at a speed of 4.63 x 10³ m/s. (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the +x axis. tes By V

One component of a magnetic field has a magnitude of 0.0450 T and points along the +x axis, while the other component has a magnitude of 0.0702 T and points along the -y axis. A particle carrying a charge of +2.23 × 10-5 C is moving along the +z axis at a speed of 4.63 x 10³ m/s. (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the +x axis. tes By V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

What is the force on an electron moving in the negative z direction with a speed of 4.1 x 106 m/s in a magnetic field of (-3.6,5.2,-2.8) mT? Give the answer as a vector
A proton moves in a helical path at speed v = 5.10 x 107 m/s high above the atmosphere, where Earth's magnetic field has magnitude B = 3.80 x 10-6 T. The proton's velocity makes an angle of 25.0° with the magnetic field. The mass of the proton is 1.673x10-27 kg. Find the radius of the helix. km
An electron is moving through a magnetic field whose magnitude is 8.7x104 T. The electron experiences only a magnetic force and has an acceleration of magnitude of 3.5 x 1014 m/s². At a certain instant, it has a speed of 6.80x10® m/s. Determine the angle e (less than 90) between the electron's velocity and the magnetic field.
A positively charged particle of mass 8.84 x 10-8 kg is traveling due east with a speed of 79.2 m/s and enters a 0.346-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 3.34 x 10-3 s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge. (a) Number i (b) Number i Units Units B (out of screen)
A positively charged particle of mass 6.82 x 10-8 kg is traveling due east with a speed of 64.2 m/s and enters a 0.397-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 4.06 × 10-³ s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge. (a) Number (b) Number pi i Units Units V < B (out of screen)
In the figure below, the current in the long, straight wire is 1=13.8 A, and the wire lies in the plane of the rectangular loop, which carries a current of I2=10.0 A. The dimensions in the figure are c= 0.100 m, a=0.150 m, and , l= 0.450 m. Find the magnitude of the net force ( in units of µN) exerted on the loop by the magnetic field created by the wire. a Select one: A. 74.5 B. 41.4 C. 46.9 D. 81.4 O E. 102.1
One component of a magnetic field has a magnitude of 0.0383 T and points along the +x axis, while the other component has a magnitude of 0.0735 T and points along the -y axis. A particle carrying a charge of +2.22 × 10-5 C is moving along the +z axis at a speed of 4.97 x 10³ m/s. (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the +x axis. (a) Number (b) Number i IN Units Units By +q
A +4.5 x 10^-12 C charged particle is moving towards west at a speed of 3 x 10^2 m/s where the magnetic field of Earth is 4 x 10^3 T directed south. What is the magnitude and direction of the magnetic force acting on the particle?
(d) Would the electron undergo the same acceleration? O Yes O No
Problem 2: = A particle with charge +2.0 C moves through a uniform magnetic field. At one instant the velocity vector is v (2î+4ĵ + 6k) m/sec and the magnetic force on the particle is F = (41-20ĵ+ 12k) N. The x and y components of the magnetic field are equal (Bx = By). Thus, the magnetic field is given by B = B×î + B×ĵ + B₂k. What are B× and B₂? Answer: Bx = -3 T and B₂ = −4 T.
A particle with charge 8.11 x 10^-6 C moves at 4.75 x 10^6 m/s through a magnetic field of strength 4.14 T. The angle between the particle s velocity and the magnetic field direction is 55.1 degrees and the particle undergoes an acceleration of 7.7 m/s^2. What is the particle s mass? 9.2 kg 16.99 kg 3.9 kg 5.4 kg
Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.88 x 10 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 2.93 x 10-8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron. HINT (a) magnitude of the magnetic force on a proton (in N) N (b) direction of the magnetic force on a proton O+x-direction O-x-direction O+y-direction O-y-direction O +z-direction -z-direction (c) magnitude of the magnetic force on an electron (in N) N (d) direction of the magnetic force on an electron +x-direction -x-direction O +y-direction O-y-direction O +z-direction O -z-direction 000