One class of models for population growth rates in marine fisheries assumes that the harvest from fishing is proportional to the population size. For one such model, we have the the following formula, where G is the growth rate of the population, in millions of tons of fish per year, and n is the population size, in millions of tons of fish. G = 0.4n 1 − n 2 − 0.2n (a) Make a graph of G versus n. Include values of n up to 1 million tons. (b) Use functional notation to express the growth rate if the population size is 0.24 million tons. G Calculate the value. (Round your answer to two decimal places.) million tons per year (c) Calculate G(1.12). (Round your answer to two decimal places.) G(1.12) = million tons per year Explain in practical terms what your answer means. If the population size is 1.12 million tons, then the growth rate is increasing at a rate of 0.03 million tons per year.If the population size is 1.12 million tons, then the population is increasing at a rate of 0.03 million tons per year. If the population size is 1.12 million tons, then the population is decreasing at a rate of 0.03 million tons per year.If the population size is 1.12 million tons, then the growth rate is decreasing at a rate of 0.03 million tons per year. (d) At what population size is the growth rate the largest? (Round your answer to two decimal places.) million tons
One class of models for population growth rates in marine fisheries assumes that the harvest from fishing is proportional to the population size. For one such model, we have the the following formula, where G is the growth rate of the population, in millions of tons of fish per year, and n is the population size, in millions of tons of fish. G = 0.4n 1 − n 2 − 0.2n (a) Make a graph of G versus n. Include values of n up to 1 million tons. (b) Use functional notation to express the growth rate if the population size is 0.24 million tons. G Calculate the value. (Round your answer to two decimal places.) million tons per year (c) Calculate G(1.12). (Round your answer to two decimal places.) G(1.12) = million tons per year Explain in practical terms what your answer means. If the population size is 1.12 million tons, then the growth rate is increasing at a rate of 0.03 million tons per year.If the population size is 1.12 million tons, then the population is increasing at a rate of 0.03 million tons per year. If the population size is 1.12 million tons, then the population is decreasing at a rate of 0.03 million tons per year.If the population size is 1.12 million tons, then the growth rate is decreasing at a rate of 0.03 million tons per year. (d) At what population size is the growth rate the largest? (Round your answer to two decimal places.) million tons
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
One class of models for population growth rates in marine fisheries assumes that the harvest from fishing is proportional to the population size. For one such model, we have the the following formula, where G is the growth rate of the population, in millions of tons of fish per year, and n is the population size, in millions of tons of fish.
G = 0.4n
1 −
− 0.2n
n |
2 |
(a) Make a graph of G versus n. Include values of n up to 1 million tons.
(b) Use functional notation to express the growth rate if the population size is 0.24 million tons.
Calculate the value. (Round your answer to two decimal places.)
million tons per year
(c) Calculate G(1.12). (Round your answer to two decimal places.)
G(1.12) = million tons per year
Explain in practical terms what your answer means.
(d) At what population size is the growth rate the largest? (Round your answer to two decimal places.)
million tons
(b) Use functional notation to express the growth rate if the population size is 0.24 million tons.
G
Calculate the value. (Round your answer to two decimal places.)
million tons per year
(c) Calculate G(1.12). (Round your answer to two decimal places.)
G(1.12) = million tons per year
Explain in practical terms what your answer means.
If the population size is 1.12 million tons, then the growth rate is increasing at a rate of 0.03 million tons per year.If the population size is 1.12 million tons, then the population is increasing at a rate of 0.03 million tons per year. If the population size is 1.12 million tons, then the population is decreasing at a rate of 0.03 million tons per year.If the population size is 1.12 million tons, then the growth rate is decreasing at a rate of 0.03 million tons per year.
(d) At what population size is the growth rate the largest? (Round your answer to two decimal places.)
million tons
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,