One card is chosen from a set of 149 cards that have ranks 1 to 7. Let X be the number on the card chosen. The distribution function for picking the cards is given as follows: m(1) = 2/149 m(2) = 10/149 m(3) = 18/149 m(4) = 32/149 m(5)= 34/149 m(6) = 28/149 m(7) = 25/149 Let E be the event "A card with an odd number is drawn" and F be the event "A card numbered 5 or more is drawn." a) Compute P(E): 0.5302 b) Compute P(E): 0.4698 c) Compute P(F): 0.5839 d) Compute P(F): 0.4161 e) Compute P(En F): 0.3960 f) Compute P(EUF): 0.5839 #

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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i figured out everything except F, the answer is not 0.5839 or 0.5302

One card is chosen from a set of 149 cards that have ranks 1 to 7. Let X be the number on the card chosen. The distribution function for picking the
cards is given as follows:
m(1) = 2/149
m(2) = 10/149
m(3)
= 18/149
=
m(4) = 32/149
m(5) = 34/149
m(6) = 28/149
m(7) = 25/149
Let E be the event "A card with an odd number is drawn"
and F be the event "A card numbered 5 or more is drawn."
a) Compute P(E): 0.5302
b) Compute P(E): 0.4698
c) Compute P(F): 0.5839
d) Compute P(F): 0.4161
e) Compute P(En F): 0.3960
f) Compute P(EUF): 0.5839
#
Transcribed Image Text:One card is chosen from a set of 149 cards that have ranks 1 to 7. Let X be the number on the card chosen. The distribution function for picking the cards is given as follows: m(1) = 2/149 m(2) = 10/149 m(3) = 18/149 = m(4) = 32/149 m(5) = 34/149 m(6) = 28/149 m(7) = 25/149 Let E be the event "A card with an odd number is drawn" and F be the event "A card numbered 5 or more is drawn." a) Compute P(E): 0.5302 b) Compute P(E): 0.4698 c) Compute P(F): 0.5839 d) Compute P(F): 0.4161 e) Compute P(En F): 0.3960 f) Compute P(EUF): 0.5839 #
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